如何在java中获取XML的价值

如何在java中解析这种类型的XML

示例

<?xml version="1.0" encoding="UTF-8" ?>
<isomsg direction="incoming">
   <id id="2" value="929501003300038807"/>
   <id id="3" value="0301100"/>
   <id id="4" value="000000000000"/>
</isomsg>

---

现在，我想获得值

9295010033000383807030110000000000000000

这里是一个使用jaxb的简单示例

假设您有以下XML，请注意我更正了

 <id="2" value="929501003300038807"/> to 

  <?xml version="1.0" encoding="UTF-8" ?>
   <isomsg direction="incoming">
       <id id="2" value="929501003300038807"/>
       <id id="3" value="0301100"/>
       <id id="4" value="000000000000"/>
  </isomsg>    

XMLRunner来测试您的课程

@XmlRootElement(name = "isomsg")
@XmlAccessorType(XmlAccessType.FIELD)
public class Isomsg
{

  @XmlElement(name = "id")
  private List<XMLObject> idList = null;

  public List<XMLObject> getIdList()
  {
    return idList;
  }

  public void setIdList(List<XMLObject> idList)
  {
    this.idList = idList;
  }
}

   public class XMLRunner
{

  public static void main(String[] args)
  {
    doFromFile("d:\\myxml.xml");
    doFromString("<?xml version=\"1.0\" encoding=\"UTF-8\" ?>\n" +
            "    <isomsg direction=\"incoming\">\n" +
            "        <id id=\"2\" value=\"929501003300038807\"/>\n" +
            "        <id id=\"3\" value=\"0301100\"/>\n" +
            "        <id id=\"4\" value=\"000000000000\"/>\n" +
            "   </isomsg>    ");
  }

  public static void doFromFile(String filename)
  {
    try
    {
      System.out.println("About to unmarshal from file : " + filename);
      File file = new File(filename);
      JAXBContext jaxbContext = JAXBContext.newInstance(Isomsg.class);

      Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
      Isomsg isomsg = (Isomsg) jaxbUnmarshaller.unmarshal(file);
      System.out.println("You have " + isomsg.getIdList().size() + " items");

      for (XMLObject xmlObject : isomsg.getIdList())
      {
        System.out.println(xmlObject.getValue());
      }
    }
    catch (JAXBException e)
    {
      e.printStackTrace();
    }
  }

  public static void doFromString(String xmlString)
  {
    try
    {
      System.out.println("About to unmarshal from string  : " + xmlString);
      JAXBContext jaxbContext = JAXBContext.newInstance(Isomsg.class);

      Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();

      StringReader reader = new StringReader(xmlString);
      Isomsg isomsg = (Isomsg) jaxbUnmarshaller.unmarshal(reader);
      System.out.println("You have " + isomsg.getIdList().size() + " items");

      for (XMLObject xmlObject : isomsg.getIdList())
      {
        System.out.println(xmlObject.getValue());
      }
    }
    catch (JAXBException e)
    {
      e.printStackTrace();
    }
  }

}

公共类XMLRunner
{
公共静态void main（字符串[]args）
{
doFromFile（“d:\\myxml.xml”）；
doFromString（“\n”+
“\n”+
“\n”+
“\n”+
“\n”+
"       ");
}
公共静态void doFromFile（字符串文件名）
{
尝试
{
System.out.println（“即将从文件中解组：“+filename”）；
文件=新文件（文件名）；
JAXBContext JAXBContext=JAXBContext.newInstance（Isomsg.class）；
解组器jaxbUnmarshaller=jaxbContext.createUnmarshaller（）；
Isomsg Isomsg=（Isomsg）jaxbUnmarshaller.unmarshal（文件）；
System.out.println（“您有”+isomsg.getIdList（）.size（）+items”）；
for（XMLObject:isomsg.getIdList（））
{
System.out.println（xmlObject.getValue（））；
}
}
捕获（JAXBEException e）
{
e、 printStackTrace（）；
}
}
公共静态void doFromString（String xmlString）
{
尝试
{
System.out.println（“即将从字符串中解组：“+xmlString”）；
JAXBContext JAXBContext=JAXBContext.newInstance（Isomsg.class）；
解组器jaxbUnmarshaller=jaxbContext.createUnmarshaller（）；
StringReader=新的StringReader（xmlString）；
Isomsg Isomsg=（Isomsg）jaxbUnmarshaller.unmarshal（reader）；
System.out.println（“您有”+isomsg.getIdList（）.size（）+items”）；
for（XMLObject:isomsg.getIdList（））
{
System.out.println（xmlObject.getValue（））；
}
}
捕获（JAXBEException e）
{
e、 printStackTrace（）；
}
}
}

帮助链接您的xml无效

id=“2

不是有效的属性实际上我想从字符串而不是文件中解析此xml，如何解决此问题。@KawshikRoy，我已经编辑了我的帖子，方法doFromString（）将从字符串中解组谢谢@Kenneth Clark:）

   public class XMLRunner
{

  public static void main(String[] args)
  {
    doFromFile("d:\\myxml.xml");
    doFromString("<?xml version=\"1.0\" encoding=\"UTF-8\" ?>\n" +
            "    <isomsg direction=\"incoming\">\n" +
            "        <id id=\"2\" value=\"929501003300038807\"/>\n" +
            "        <id id=\"3\" value=\"0301100\"/>\n" +
            "        <id id=\"4\" value=\"000000000000\"/>\n" +
            "   </isomsg>    ");
  }

  public static void doFromFile(String filename)
  {
    try
    {
      System.out.println("About to unmarshal from file : " + filename);
      File file = new File(filename);
      JAXBContext jaxbContext = JAXBContext.newInstance(Isomsg.class);

      Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
      Isomsg isomsg = (Isomsg) jaxbUnmarshaller.unmarshal(file);
      System.out.println("You have " + isomsg.getIdList().size() + " items");

      for (XMLObject xmlObject : isomsg.getIdList())
      {
        System.out.println(xmlObject.getValue());
      }
    }
    catch (JAXBException e)
    {
      e.printStackTrace();
    }
  }

  public static void doFromString(String xmlString)
  {
    try
    {
      System.out.println("About to unmarshal from string  : " + xmlString);
      JAXBContext jaxbContext = JAXBContext.newInstance(Isomsg.class);

      Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();

      StringReader reader = new StringReader(xmlString);
      Isomsg isomsg = (Isomsg) jaxbUnmarshaller.unmarshal(reader);
      System.out.println("You have " + isomsg.getIdList().size() + " items");

      for (XMLObject xmlObject : isomsg.getIdList())
      {
        System.out.println(xmlObject.getValue());
      }
    }
    catch (JAXBException e)
    {
      e.printStackTrace();
    }
  }

}