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Java 如何从Hibernate中的第三个表中获取属性? 公共类菜单{ 私有int-menuId; 私有字符串名称; private Set items=new HashSet(); } 公共类项目{ 私有int-itemId; 私有字符串名称; 私人浮重; 私有集菜单=新HashSet(); }_Java_Hibernate_Spring_Struts2_Hql - Fatal编程技术网

Java 如何从Hibernate中的第三个表中获取属性? 公共类菜单{ 私有int-menuId; 私有字符串名称; private Set items=new HashSet(); } 公共类项目{ 私有int-itemId; 私有字符串名称; 私人浮重; 私有集菜单=新HashSet(); }

Java 如何从Hibernate中的第三个表中获取属性? 公共类菜单{ 私有int-menuId; 私有字符串名称; private Set items=new HashSet(); } 公共类项目{ 私有int-itemId; 私有字符串名称; 私人浮重; 私有集菜单=新HashSet(); },java,hibernate,spring,struts2,hql,Java,Hibernate,Spring,Struts2,Hql,重量属性应在第三个表“菜单项”中 菜单的xml public class Menu { private int menuId; private String name; private Set<Item> items=new HashSet<Item>(); } public class Item { private int itemId; private String name; private Float weight; p

重量属性应在第三个表“菜单项”中

菜单的xml

public class Menu { 
  private int menuId; 
  private String name;
  private Set<Item> items=new HashSet<Item>(); 

} 
public class Item { 
  private int itemId; 
  private String name; 
  private Float weight;
  private Set<Menu> menus=new HashSet<Menu>();
}

项目的xml:

<class name="Menu" table="menu">
    <id name="menuId" type="java.lang.Integer" column="menuId">
        <generator class="increment"></generator>
    </id>
    <property name="name" type="string" column="menuName" length="100"></property>
    <set access="property" lazy="true" inverse="false" cascade="save-update"
        name="items" batch-size="10" fetch="select" table="menu_item">
        <key column="menuId" />
        <many-to-many class="Item" column="itemId" />
    </set>

mysql中的第三个表菜单项: menuId、itemId、weight


但是我怎样才能得到重量的值呢?是否要在菜单的xml中写入一些内容?

您需要为第三个表创建一个新实体(MenuItem):

<class name="Item" table="item">
    <id name="itemId" type="java.lang.Integer" column="itemId">
        <generator class="increment"></generator>
    </id>
    <property name="name" type="string" column="itemName" length="100"></property>
    <set access="property" lazy="true" inverse="false" cascade="save-update"
        name="menus" batch-size="10" fetch="select" table="menu_item">
        <key column="itemId" />
        <many-to-many class="Menu" column="menuId" />
    </set>
</class>

您的映射将从多到多再到一到多,例如:

<class name="MenuItem" table="menu_item" mutable="false">
   <composite-id name="id" class="MenuItem$Id">
     <key-property name="menuId" access="field" column="menu_id"/>
     <key-property name="itemId" access="field" column="item_id"/>
   </composite-id>
   <property name="weight" column="weight" type="string" not-null="true"/>
   <many-to-one name="menu" column="menu_id" not-null="true" insert="false" update="false"/>
   <many-to-one name="item" column="item_id" not-null="true" insert="false" update="false"/>
</class>

另一种方法是使MenuItem类仅@Embeddeble并映射组件集合:

<set name="items" inverse="true">
   <key column="item_id"/>
   <one-to-many class="MenuItem"/>
</set>

<class name="Menu" table="menu">
   <set name="menuItems" table="menu_item">
       <key column="menu_id"/>
       <composite-element class="MenuItem">
           <parent name="menu"/>
           <many-to-one name="item" column="menu_id" not-null="true" class="Item"/>
           <property name="weight" column="weight"/>
        </composite-element>
   </set>
</class>