Java 字符不能转换为布尔值?
这是我做的第一个项目,所以我知道有很多错误。我正在尝试使用嵌套的if-else语句创建计算器。我得到的唯一错误是,在if语句中,我不能从char转换为boolean。我不知道为什么它会认为我在尝试转换为布尔值,但我猜“=A”等可能会让它这么想?如有任何建议,将不胜感激Java 字符不能转换为布尔值?,java,char,boolean,Java,Char,Boolean,这是我做的第一个项目,所以我知道有很多错误。我正在尝试使用嵌套的if-else语句创建计算器。我得到的唯一错误是,在if语句中,我不能从char转换为boolean。我不知道为什么它会认为我在尝试转换为布尔值,但我猜“=A”等可能会让它这么想?如有任何建议,将不胜感激 public static void main(String[] args) { //main class char result = 0; //define and declare variables doubl
public static void main(String[] args) { //main class
char result = 0; //define and declare variables
double firstNumber = 0;
double secondNumber = 0;
double answer = 0;
System.out.println("Calculator Program\n"); //Text for user
System.out.println("Choose how to proceed:\n");
System.out.println("A. Add\n");
System.out.println("B. Subtract\n");
System.out.println("C. Multiply\n");
System.out.println("D. Divide\n");
Scanner userInput = new Scanner(System.in); //create new Scanner
result = userInput.next().charAt(0); //Take only the first letter entered
if (result = A){
System.out.println("Please enter the first number: ");
firstNumber = userInput.nextDouble(); //redefine first number
userInput.next(); //clears line
System.out.println("Please enter the second number: ");
secondNumber = userInput.nextDouble(); //redefine second number
userInput.next(); //clears line
answer = firstNumber + secondNumber; //algorithim
System.out.println("Answer: " + firstNumber + " + " + secondNumber + " = " + answer);//print answer
}
else if ( result = B){
System.out.println("Please enter the first number: ");
firstNumber = userInput.nextDouble(); //redefine first number
userInput.next(); //clears line
System.out.println("Please enter the second number: ");
secondNumber = userInput.nextDouble(); //redefine second number
userInput.next(); //clears line
answer = firstNumber - secondNumber; //algorithim
System.out.println("Answer: " + firstNumber + " - " + secondNumber + " = " + answer);//print answer
}
else if ( result = C){
System.out.println("Please enter the first number: ");
firstNumber = userInput.nextDouble(); //redefine first number
userInput.next(); //clears line
System.out.println("Please enter the second number: ");
secondNumber = userInput.nextDouble(); //redefine second number
userInput.next(); //clears line
answer = firstNumber * secondNumber; //algorithim
System.out.println("Answer: " + firstNumber + " * " + secondNumber + " = " + answer);//print answer
}
else if ( result = D){
System.out.println("Please enter the first number: ");
firstNumber = userInput.nextDouble(); //redefine first number
userInput.next(); //clears line
System.out.println("Please enter the second number: ");
secondNumber = userInput.nextDouble(); //redefine second number
userInput.next(); //clears line
answer = firstNumber / secondNumber; //algorithim
System.out.println("Answer: " + firstNumber + " / " + secondNumber + " = " + answer);//print answer
}
}
}
字符
不能转换为布尔值
好像你想做支票。你可以这样做
String sum = "0+3";
boolean isPlus = (sum.charAt(1) == '+');
isPlus
现在将保持为真,因为在为结果赋值的if块中,sum
索引1处的字符是“+”。
如果(result=='A')/'A'不是A,您应该这样做:
if (result == 'A')
将
A
更改为'A'
,=
更改为=
,以匹配您需要将if语句更改为if(result='A')而不是if(result==A)的字符
以下代码将使您更清楚:
import java.util.Scanner;
public class checkBoolToChar {
public static void main(String[] args) {
char a = 0;
Scanner in = new Scanner(System.in);
a = in.next().charAt(0);
if(a == 'A'){
System.out.println("Match ");
}
}
}
当您将条件写为
if(result = A)
它实际上是给结果变量赋值。现在,由于A不是用引号写的,所以它假设A是一个变量,但由于它没有在程序中的任何地方声明,所以它假设A是一个布尔值。但是结果的数据类型是char。因此,它会给您带来数据类型不匹配错误。如果你把它写成
if(result == "A")
它将检查字母是否为A,错误将被删除。赋值与相等。(
=
vs.=
)和字符文字被单引号('A'
)包围。正确:赋值表达式的类型是分配给的变量的类型。因此表达式aChar='?'
被类型化为char
,但是if
只接受布尔型表达式。然后问题是“为什么=没有达到预期效果?”,对于这个问题,已有大量的教程/书籍/参考:)或者他在if
语句中使用赋值运算符。@JonnyHenly-Yep。我的答案中也包含了这一点,显示了==是如何生成布尔值的