首次在JAVA中使用方法和构造函数,在程序中接收错误以确定加薪
我正在编写一个相当简单的程序,只需输出两名员工的姓名、工资以及工资的10%。 我有两个问题:1)工资打印为“$0.000000”2)我无法使加薪方法正常工作 这是我的密码:首次在JAVA中使用方法和构造函数,在程序中接收错误以确定加薪,java,methods,constructor,setter,getter,Java,Methods,Constructor,Setter,Getter,我正在编写一个相当简单的程序,只需输出两名员工的姓名、工资以及工资的10%。 我有两个问题:1)工资打印为“$0.000000”2)我无法使加薪方法正常工作 这是我的密码: public class Employee { // instance variable private String name; private String lastName; private double salary; // setters public St
public class Employee {
// instance variable
private String name;
private String lastName;
private double salary;
// setters
public String getLastName() { return lastName; }
public String getName() { return name; }
public double getSalary() { return salary; }
public void raise(double raise) { salary = salary + (salary * .1); }
// getters
public Employee(String name, String lastName, double salary) {
this.name = name;
this.lastName = lastName;
if (salary > 0.0) {
this.salary = salary;
}
}
}
public class EmployeeTest {
public static void main(String[] args) {
Employee raise1 = new Employee("Betty", "Jones", 4000.0);
Employee raise2 = new Employee("Sally", "Mae", 6000.0);
// Print statements for the employee's name and salary
System.out.printf("Employee #1\nFirst Name: %s\nLast Name: %s\n\n" + "Salary: $%f", raise1.getName(), raise1.getLastName(), raise1.getSalary());
// THIS IS WHERE I'M HAVNG TROUBLE
System.out.printf("Her raise will be: %d", raise1.raise(salary));
System.out.printf("Employee #1\nFirst Name: %s\nLast Name: %s\n\n" + "Salary: %f", raise1.getName(), raise1.getLastName(), raise1.getSalary());
raise2.raise(salary);
}
}
提前感谢您的帮助 您的raise()
方法的返回类型为void,这意味着它根本不会返回任何内容。将返回类型更改为双倍,只需键入返回此项。最后的工资
应该可以。应该是这样的:
public double raise(double salary)
{
this.salary = salary + (salary * 0.1);
return this.salary;
}
this
关键字引用您正在使用的对象的实例。简单地说,您可能希望引用classsalary
变量,而不是方法中传递的参数,否则它将引用传入的参数
你还需要调用this.salary=salary
在构造函数中,因为以前分配它的唯一方法是salary
低于零,但4000不低于零 当你这样做的时候
Employee raise1= new Employee("Betty","Jones",4000.0);
调用具有以下条件的Employee
类的构造函数:
if (salary <0.0){
this.salary = salary;
}
if(salarysalary打印$0.00000的原因是因为您出于某种原因放置了if语句,而不是仅仅设置传递给构造函数的salary。第二件事,void方法不会返回任何东西,这就是raise方法无法按您希望的方式工作的原因。我为您修复了它,所以请看一看,希望我能帮助您理解其中的原因你做错了,如果你有任何问题,尽管问我,我在这里等你
员工考试类别:
public class EmployeeTest {
public static void main(String[] args) {
Employee raise1= new Employee("Betty","Jones",4000.0);
Employee raise2= new Employee("Sally","Mae",6000.0);
//Print statements for the employee's name and salary
System.out.printf("Employee #1\nFirst Name: %s\nLast Name: %s\n\n" +
"Salary: $%.2f",
raise1.getName(),
raise1.getLastName(),
raise1.getSalary());
System.out.printf("\nHer raise will be: $%.2f",
raise1.raise(raise1.getSalary()));
System.out.printf("\n\nEmployee #2\nFirst Name: %s\nLast Name: %s\n\n" +
"Salary: $%.2f",
raise2.getName(),
raise2.getLastName(),
raise2.getSalary());
System.out.printf("\nHer raise will be: $%.2f\n",
raise2.raise(raise2.getSalary()));
}
}
public class Employee {
//instance variable
private String name;
private String lastName;
private double salary;
//getters
public String getLastName() {
return lastName;
}
public String getName() {
return name;
}
public double getSalary() {
return salary;
}
public double raise(double raise){
salary = salary + (salary*.1);
return salary;
}
//constructor
public Employee(String name, String lastName, double salary){
this.name = name;
this.lastName = lastName;
this.salary = salary;
}
}
员工类别:
public class EmployeeTest {
public static void main(String[] args) {
Employee raise1= new Employee("Betty","Jones",4000.0);
Employee raise2= new Employee("Sally","Mae",6000.0);
//Print statements for the employee's name and salary
System.out.printf("Employee #1\nFirst Name: %s\nLast Name: %s\n\n" +
"Salary: $%.2f",
raise1.getName(),
raise1.getLastName(),
raise1.getSalary());
System.out.printf("\nHer raise will be: $%.2f",
raise1.raise(raise1.getSalary()));
System.out.printf("\n\nEmployee #2\nFirst Name: %s\nLast Name: %s\n\n" +
"Salary: $%.2f",
raise2.getName(),
raise2.getLastName(),
raise2.getSalary());
System.out.printf("\nHer raise will be: $%.2f\n",
raise2.raise(raise2.getSalary()));
}
}
public class Employee {
//instance variable
private String name;
private String lastName;
private double salary;
//getters
public String getLastName() {
return lastName;
}
public String getName() {
return name;
}
public double getSalary() {
return salary;
}
public double raise(double raise){
salary = salary + (salary*.1);
return salary;
}
//constructor
public Employee(String name, String lastName, double salary){
this.name = name;
this.lastName = lastName;
this.salary = salary;
}
}
打印上述程序的输出:
public class EmployeeTest {
public static void main(String[] args) {
Employee raise1= new Employee("Betty","Jones",4000.0);
Employee raise2= new Employee("Sally","Mae",6000.0);
//Print statements for the employee's name and salary
System.out.printf("Employee #1\nFirst Name: %s\nLast Name: %s\n\n" +
"Salary: $%.2f",
raise1.getName(),
raise1.getLastName(),
raise1.getSalary());
System.out.printf("\nHer raise will be: $%.2f",
raise1.raise(raise1.getSalary()));
System.out.printf("\n\nEmployee #2\nFirst Name: %s\nLast Name: %s\n\n" +
"Salary: $%.2f",
raise2.getName(),
raise2.getLastName(),
raise2.getSalary());
System.out.printf("\nHer raise will be: $%.2f\n",
raise2.raise(raise2.getSalary()));
}
}
public class Employee {
//instance variable
private String name;
private String lastName;
private double salary;
//getters
public String getLastName() {
return lastName;
}
public String getName() {
return name;
}
public double getSalary() {
return salary;
}
public double raise(double raise){
salary = salary + (salary*.1);
return salary;
}
//constructor
public Employee(String name, String lastName, double salary){
this.name = name;
this.lastName = lastName;
this.salary = salary;
}
}
员工#1
名字:贝蒂
姓:琼斯
薪金:4000美元
她的加薪是:4400美元
员工#2
名字:莎莉
姓:梅
薪金:6000美元
她的加薪将是:$6600.00你的“getter”和“setters”评论有点……误导性。你的raise
方法是void
类型,这意味着它不会向你的系统.out.printf
行返回任何内容。如果(工资1.如PM77-1所述,您编写了代码以防止工资被初始化。2.什么是“正确的”你的raise
方法应该如何工作?我只是在解释我正在使用的书中的问题时有错误的逻辑。它说如果工资低于0,就不要传递它。我还想知道我如何修正关于加薪的打印声明。我编辑了上面的代码以显示我的更改,这就是我刚刚编辑它的原因。我意识到这个错误或者。仍然无法解决问题。零的110%仍然是零。该方法很好。不是在上下文中使用它。他在printf
语句中使用它,这要求返回类型不是void,而是void,以便它实际显示某个内容。System.out.printf(“她的加薪将是:%d”,raise1.raise(salary))
查看他的main()方法。非常感谢。这是我第一次用Java编写代码,我还不熟悉语法。