Java if语句中的返回循环

你能帮我查一下这个密码吗

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非常感谢您的任何建议-Newbie2Java 我有一些很好的建议-谢谢（错过链接）

这是我的代码：

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导入java.util.Scanner

公开课问题5WIP{

/**
 * @param args


public static void main(String[] args) {
    // TODO Auto-generated method stub
    // boolean correctInput = false; // assume we dont have correct input
    //  while (!correctInput){       // continue as long as not correct input

    int hourValue = 0;
    Scanner in;
    while (!(hourValue > 0 && hourValue <= 12)) {
        System. out.println("Please enter the hours (between 1 and 12): ");                                  
        in = new Scanner(System.in); // User input hour value.

        hourValue = in.nextInt();

        if (!(hourValue > 0 && hourValue <= 12)) {
            System.out.println("Hour Value should be between 1 and 12, please try again "); // invalid hours.

        }
    }

    int minuteValue = 0;
    // Scanner in;
    while (!(minuteValue > 0 && hourValue <= 60)) {
        System. out.println("Please enter the minutes (between 1 and 60): ");                                  
        in = new Scanner(System.in); // User input hour value.

        minuteValue = in.nextInt();

        if (!(minuteValue > 0 && minuteValue <= 60)) {
            System.out.println("Invalid entry, please try again: "); // invalid hours.
            return;
        }

/**
*@param args
公共静态void main（字符串[]args）{
//TODO自动生成的方法存根
//boolean correctInput=false；//假设没有正确的输入
//而（！correctInput）{//只要输入不正确，就继续
int hourValue=0；
扫描仪输入；
while（！（hourValue>0&&hourValue 0&&hourValue 0&&hourValue 0&&minuteValue使用while循环执行此操作！如下所示：

int hourValue; 
while(!(hourValue > 0 && hourValue <= 12)) {
    System.out.println("Please enter the hours (between 1 and 12): "); //The program prompts for the hour. 
    Scanner in = new Scanner(System.in); // User input hour value.

    hourValue = in.nextInt();        

    if(!(hourValue > 0 && hourValue <= 12)){
           System.out.println("Hour Value should be between 1 and 12, please try again "); //invalid hours.
           return; 

    }
}

    int minuteValue; 
    System.out.println("Please enter the minutes (between 1 and 60): "); //The program prompts for the hour. 
    in = new Scanner(System.in); // User input hour value.

    minuteValue = in.nextInt();        

    if(!(minuteValue >= 0 && minuteValue <= 60)){
           System.out.println("Minute Value should be between 0 and 60, please try again "); //invalid minutes. 
           return;

inthourvalue；
当（！（hourValue>0&&hourValue 0&&hourValue=0&&minuteValue试着给出正确的答案

   import java.util.Scanner;

   public class Test {

public static void main(String[] args) {

    int hourValue = 0;
    Scanner in;
    while (!(hourValue > 0 && hourValue <= 12)) {
        System. out.println("Please enter the hours (between 1 and 12): ");                                  
        in = new Scanner(System.in); // User input hour value.

        hourValue = in.nextInt();

        if (!(hourValue > 0 && hourValue <= 12)) {
            System.out.println("Hour Value should be between 1 and 12,
                        please try again "); // invalid hours.

        }
    }

    int minuteValue;
    System.out.println("Please enter the minutes (between 1 and 60): ");
        // The program prompts for the hour.
    in = new Scanner(System.in); // User input hour value.

    minuteValue = in.nextInt();

    if (!(minuteValue >= 0 && minuteValue <= 60)) {
        System.out.println("Minute Value should be between 0 and 60,
                     please  try again "); // invalid minutes.
        return;

    }
}

import java.util.Scanner；
公开课考试{
公共静态void main（字符串[]args）{
int hourValue=0；
扫描仪输入；
而（！（hourValue>0&&hourValue=0&&minuteValue
import java.util.Scanner；
公开课考试{
公共静态void main（字符串[]args）{
单位值，分钟值；
扫描仪输入；
while（true）{
System.out.println（“请输入小时数（介于1和12之间）：”；
in=新扫描仪（System.in）；//用户输入小时值。
hourValue=in.nextInt（）；
如果（小时值<0 | |小时值>12））
System.out.println（“小时值应介于1和12之间，请重试”）；
其他的
打破
}
while（true）{
System.out.println（“请输入分钟数（介于1和60之间）：”；
in=新扫描仪（System.in）；
minuteValue=in.nextInt（）；
如果（分钟值<0 | |分钟值>60））
System.out.println（“分钟值应介于0和60之间，请重试”）；//分钟无效。
其他的
打破
}   
}
}
导入java.util.Scanner

公开课考试{

公共静态void main（字符串[]args）{

int hourValue=0；
扫描仪输入；
而！（hourValue>0&&hourValue 0&&hourValue=0&&minuteValue这似乎与javascript无关。在第二个
if
中，您不需要返回语句，因为您必须循环才能再次输入小时值。相反，如果可以接受小时，您必须添加额外的else块，并从循环中断。谢谢您的帖子，mo很有帮助。@Rouxster如果它对你有帮助，给他们一个投票和/或接受回答谢谢你的帖子，非常有帮助。
import java.util.Scanner;

public class Test {
    public static void main(String[] args) {
        int hourValue, minuteValue;
        Scanner in;

        while (true) {
            System. out.println("Please enter the hours (between 1 and 12): ");
            in = new Scanner(System.in); // User input hour value.
            hourValue = in.nextInt();
            if (hourValue < 0 || hourValue > 12)) 
                System.out.println("Hour Value should be between 1 and 12, please try again ");
            else
                break;
        }

        while(true) {
            System.out.println("Please enter the minutes (between 1 and 60): ");
            in = new Scanner(System.in);
            minuteValue = in.nextInt();
            if (minuteValue < 0 || minuteValue > 60)) 
                System.out.println("Minute Value should be between 0 and 60,please  try again ");//invalid minutes.
            else
                break;
        }   
    }
}

int hourValue = 0;
Scanner in;
while (!(hourValue > 0 && hourValue <= 12)) {
    System. out.println("Please enter the hours (between 1 and 12): ");                                  
    in = new Scanner(System.in); // User input hour value.

    hourValue = in.nextInt();

    if (!(hourValue > 0 && hourValue <= 12)) {
        System.out.println("Hour Value should be between 1 and 12,
                    please try again "); // invalid hours.

    }
}

int minuteValue;
System.out.println("Please enter the minutes (between 1 and 60): ");
    // The program prompts for the hour.
in = new Scanner(System.in); // User input hour value.

minuteValue = in.nextInt();

if (!(minuteValue >= 0 && minuteValue <= 60)) {
    System.out.println("Minute Value should be between 0 and 60,
                 please  try again "); // invalid minutes.
    return;