Java 为什么servlet中的请求参数为null？

从我的表单中，我已经将一个特定的数据库列放入jsp表单中的输入框中，这是成功的，但是问题是，我也希望使用请求参数将其放入后端，但结果是得到null

jsp表单代码：

<form style="height: 100% ; width: 100% ; margin-top: 5% ; margin-right: 0%" method="GET">
                    
                            <table class="styled-table" style="margin-bottom: 15px; margin-top:0%; height: 80%">
                                <thead>
                                    <tr>
                                        <th>Doctor Name</th>  
                                        <th>Speciality</th>  
                                        <th>Channel</th>  
                                        
                                    </tr>
                                </thead>
                                        <tbody>
                                <%
                                    String input = request.getParameter("input");

                                    Connection con = DriverManager.getConnection("jdbc:mysql://localhost:3306/hms", "root", "");
                                    Statement st = con.createStatement();
                                    ResultSet rs = null;
                                    String strQuery;
                                    if (input != null) {
                                        strQuery = " SELECT * FROM staff WHERE Staff_Name like '%" + input + "%' or Staff_speciality like '%" + input + "%' AND Position= 'Doctor'  ";
                                    } else {
                                        strQuery = "SELECT * FROM staff WHERE Position= 'Doctor' ";
                                    }
                                    rs = st.executeQuery(strQuery);
                                    if (rs != null) {
                                        while (rs.next()) {
                                %>
                                <tr class="row">
                                    <td><%=rs.getString("Staff_Name")%><input name="docname" type="text"  value="<%=rs.getString("Staff_Name")%>"></td>
                                    <td><%=rs.getString("Staff_speciality")%></td>
                                    
                                   
                                    <td><a title="Channel Now " style=" display: flex; justify-content:center; align-items: center; color:#39447a;" href="<%=request.getContextPath()%>/ChannelDoc/channel"><i style="margin-left: 4%;" class="fa fa-address-card-o"></i></a></td>
                                </tr>
                                <% }
                                    }
                                %>
                            </tbody> 
                               
                            </table >
                        </form>

servlet为我提供空值，因此我无法继续进行其他后端工作，如果能在servlet中获得docname值，我们将不胜感激

---

提前感谢您。

如何将

输入发送到servlet？发送到servlet的代码是：请不要对此使用注释。请回答您的问题。一般来说，请提供一个。注意，谢谢@FedericoklezCulloca
<a title="Channel Now " style=" display: flex; justify-content:center; align-items: center; color:#39447a;" href="<%=request.getContextPath()%>/ChannelDoc/channel">

@Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        if (request.getServletPath().contains("/channel")) {
            
           String name=request.getParameter("docname");
           System.out.print(name);
}