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Java 通过映射的永久属性的反射访问字段时出错_Java_Sql_Spring_Spring Security_H2 - Fatal编程技术网

Java 通过映射的永久属性的反射访问字段时出错

Java 通过映射的永久属性的反射访问字段时出错,java,sql,spring,spring-security,h2,Java,Sql,Spring,Spring Security,H2,我已经用一对多关系设置了我的数据库,在尝试注册用户(将其保存到数据库)后,我得到了whitelabe错误页面 “访问字段[private java.lang.Integer]时出错 com.m2.cfg.domain.Fakultet.id]通过永久属性的反射 错误接下来是一对多关系:一个Fakultet(大学)可以有多个用户Fakultet(大学)类 用户类别: @Entity @Table(name = "users") public class Users {

我已经用一对多关系设置了我的数据库,在尝试注册用户(将其保存到数据库)后,我得到了whitelabe错误页面

“访问字段[private java.lang.Integer]时出错 com.m2.cfg.domain.Fakultet.id]通过永久属性的反射

错误
接下来是一对多关系:一个Fakultet(大学)可以有多个用户
Fakultet(大学)类

用户类别:

@Entity
@Table(name = "users")
public class Users {
    @Id
    @Column
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id = 0;
    @Column(name = "username")
    private String username;
    @Column(name="email")
    private String email;
    @Column(name="password")
    private String password;
    @Column(name = "enabled")
    private boolean enabled = true;
    @ManyToOne(fetch = FetchType.LAZY, targetEntity = Fakultet.class)
    @JoinColumn(name="id_fakulteta", referencedColumnName = "id")
    private Integer idFakulteta;

    public Users(){};

    public Users(String username, String email, String password, Integer idFakulteta) {
        this.username = username;
        this.email = email;
        this.password = password;
        this.idFakulteta = idFakulteta;
    }

    ..getters and setters
}
Sql脚本:

DROP TABLE IF EXISTS employee;
DROP TABLE IF EXISTS users;
DROP TABLE IF EXISTS authorities;
DROP TABLE IF EXISTS kolegiji;

CREATE TABLE employee (
      empId VARCHAR(10) NOT NULL,
      empName VARCHAR(100) NOT NULL
);

create table users (
       id INT AUTO_INCREMENT PRIMARY KEY,
       username varchar(255) not null ,
       email varchar(255),
       password varchar(255) not null,
       id_fakulteta int,
       enabled boolean
);

CREATE TABLE IF NOT EXISTS fakulteti (
     naziv VARCHAR(255) NULL,
     id INT NOT NULL,
     PRIMARY KEY (id),
     CONSTRAINT fk_fakulteti_users1
         FOREIGN KEY (id)
             REFERENCES users (id_fakulteta)
             ON DELETE NO ACTION
             ON UPDATE NO ACTION
);

create table authorities (
         username varchar(50) not null,
         authority varchar(50) not null,
         foreign key (username) references users (username)
);

CREATE TABLE kolegiji (
      id int NOT NULL AUTO_INCREMENT,
      naziv varchar(255) DEFAULT NULL,
      PRIMARY KEY (id)
);

CREATE TABLE IF NOT EXISTS teme (
     idteme INT NOT NULL AUTO_INCREMENT,
     naslov VARCHAR(255) NOT NULL,
     datumKreiranja DATE NOT NULL,
     kolegijId INT NULL,
     PRIMARY KEY (idteme),
     CONSTRAINT fk_teme_kolegiji1
         FOREIGN KEY (kolegijId)
             REFERENCES kolegiji (id)
             ON DELETE NO ACTION
             ON UPDATE NO ACTION
);
create INDEX fk_teme_kolegiji1_idx on teme(kolegijId ASC);

CREATE TABLE IF NOT EXISTS komentari (
      id INT NOT NULL AUTO_INCREMENT,
      idTeme INT NOT NULL,
      PRIMARY KEY (id),

      CONSTRAINT fk_komentari_teme
          FOREIGN KEY (idTeme)
              REFERENCES teme (idteme)
              ON DELETE NO ACTION
              ON UPDATE NO ACTION
);
create INDEX fk_komentari_teme_idx on komentari(idTeme ASC);


CREATE TABLE IF NOT EXISTS kolegiji_has_fakulteti(
   kolegiji_id INT NOT NULL,
   fakulteti_id INT NOT NULL,
   PRIMARY KEY (kolegiji_id, fakulteti_id),
   CONSTRAINT fk_kolegiji_has_fakulteti_kolegiji1
       FOREIGN KEY (kolegiji_id)
           REFERENCES kolegiji (id)
           ON DELETE NO ACTION
           ON UPDATE NO ACTION,
   CONSTRAINT fk_kolegiji_has_fakulteti_fakulteti1
       FOREIGN KEY (fakulteti_id)
           REFERENCES fakulteti (id)
           ON DELETE NO ACTION
           ON UPDATE NO ACTION
);
create INDEX fk_kolegiji_has_fakulteti_fakulteti1_idx on kolegiji_has_fakulteti(fakulteti_id ASC);
create INDEX fk_kolegiji_has_fakulteti_kolegiji1_idx on kolegiji_has_fakulteti(kolegiji_id ASC);


insert into users(username, password, enabled, id_fakulteta, email)
    values('javainuse', 'javainuse',true, 1,'nekimail@gmail.com');
insert into authorities(username,authority)values('javainuse','ROLE_ADMIN');

insert into fakulteti(naziv, id) values('TVZ', 1);

我犯的错误就在这一行

    @ManyToOne(fetch = FetchType.LAZY, targetEntity = Fakultet.class)
    @JoinColumn(name="id_fakulteta", referencedColumnName = "id")
    private Integer idFakulteta;
当连接列时,必须创建要连接的对象,并且线条需要如下所示

    @ManyToOne(fetch = FetchType.LAZY, targetEntity = Fakultet.class, cascade=CascadeType.ALL)
    @JoinColumn(name="id_fakulteta", nullable = false)
    private Fakultet faks;
我还需要删除

整数idFakulteta

字段以避免将同一列映射两次错误

    @ManyToOne(fetch = FetchType.LAZY, targetEntity = Fakultet.class, cascade=CascadeType.ALL)
    @JoinColumn(name="id_fakulteta", nullable = false)
    private Fakultet faks;