java中用于检查一个形状是否在另一个形状中的较小代码

嗨，我有一个代码来检查一个形状是圆形还是方形包围着另一个。我用过这个代码。如果此对象包含传递的形状，则为true。有人能给我一个改进或更好的替代方法吗。提前感谢：

如果这是有效的代码，那么这个问题可能是一个很好的候选。此代码有效。但我在找更小的。那我就去那里寻求帮助。。谢谢：

public boolean envelops(Shape s) { 
    boolean flag = true;
  double distance = 0.0;
  if(s instanceof Square){ //check if the shape is a Square
     Point bottomLeft= new Point(((Square)s).getTopLeft().getX(),((Square)s).getTopLeft().getY()-((Square)s).getSideLength()); //calculating the cordinates of the square 
     Point bottomRight= new Point(((Square)s).getTopLeft().getX()+((Square)s).getSideLength(),((Square)s).getTopLeft().getY()-((Square)s).getSideLength());   
     Point topRight= new Point(((Square)s).getTopLeft().getX()+  ((Square)s).getSideLength(),((Square)s).getTopLeft().getY());

     ArrayList<Point> points = new ArrayList<Point>(); //storing points in a ArrayList of points
     points.add(((Square)s).getTopLeft());
     points.add(bottomLeft);
     points.add(topRight);
     points.add(bottomRight);
        for(int i=0; i<points.size(); i++)
           {
              distance= this.center.distance(points.get(i));  //finding ditance of each cordinate from the center of the circle
              if(distance-this.radius>Shape.TOLERANCE) flag= false;      //if the distance is greater than the radius then flag becomes false, ie., the cordinate is outside the circle                                          

           }                    
     } 

  if(s instanceof Circle){
     distance=this.center.distance(((Circle)s).getCenter());  //finding distance between the centers of the 2 circles
     distance= distance +((Circle)s).getRadius();
     if(distance- this.getRadius()> Shape.TOLERANCE || distance==this.getRadius()){ //The method will return false if both circles have 0 radius
        flag=false;                                           //make flag false if the distance is more than the radius of the object Circle
     }
  }

  return flag;
}