Java 使用SpringMVC从JSP获取值

Java 使用SpringMVC从JSP获取值,java,spring,jsp,model-view-controller,Java,Spring,Jsp,Model View Controller,我在/target/m2e wtp/web资源中有maven生成的Spring项目和我的JSP insert.JSP,它如下所示: <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.

我在/target/m2e wtp/web资源中有maven生成的Spring项目和我的JSP insert.JSP,它如下所示:

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>Library</title>
</head>
<body>
    <h1>Insert record</h1>
    <form action="InsertBook" method="POST">
        Title: <input type="text" name="title"/><br>
        Author: <input type="text" name="author"/><br>
        Category: <select name="category">
            <c:forEach var="cat" items="${categories}">
                <option>${cat}</option>
            </c:forEach>
        </select>
        <input type="submit" value="insert"/>
    </form>
</body>
和servlet-context.xml代码:

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:beans="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc                 http://www.springframework.org/schema/mvc/spring-mvc.xsd
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">

<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->

<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />

<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" /> 

<!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <beans:property name="prefix" value="/WEB-INF/views/" />
    <beans:property name="suffix" value=".jsp" />
</beans:bean>

<context:component-scan base-package="com.mypackage.web" />
<resources location="/resources/**" mapping="/src/webapp/resources"/>

我在尝试访问此JSP时收到来自tomcat server的消息:

INFO : com.mypackage.web.HomeController - Welcome home! The client locale is cs.
WARN : org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request         with URI [/web/<c:url value=] in DispatcherServlet with name 'appServlet'
INFO:com.mypackage.web.HomeController-欢迎回家!客户端语言环境是cs。

警告:org.springframework.web.servlet.PageNotFound-未找到具有URI的HTTP请求的映射[/web/在这里,您的需求可能已经晚了,但是您应该实现一个控制器并使用您在web.xml中定义的Spring DispatcherServlet。如果您继续使用xml应用程序上下文配置,那么您可以定义控制器bean和其他bean(例如DAO、服务或其他组件)在applicationContext文件中,以及URLViewResolver等项(Spring3还允许应用程序上下文的Java配置方法)


SpringMVC
index.jsp
春天
org.springframework.web.servlet.DispatcherServlet
1.
春天
*.html


...

事情是让Spring(以及您决定使用的任何ORM)运行简化您的Java代码。我建议您阅读Craig Walls的《Spring in Action》一书中提供的教程或示例。这些教程帮助我们的一些新开发人员更好地理解Spring。

如果您想使用SpringMVC,您不应该实现自己的servlet。所有内容都经过了路由通过Spring自己的dispatcher servlet。我不知道如何通过编写一个完整的“Spring MVC入门教程”来回答您的问题,互联网上有很多这样的教程。Spring的PetClinic示例应用程序是一个很好的起点。啊,所以……似乎我还不明白Spring是如何工作的……谢谢评论;)
INFO : com.mypackage.web.HomeController - Welcome home! The client locale is cs.
WARN : org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request         with URI [/web/<c:url value=] in DispatcherServlet with name 'appServlet'
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    id="WebApp_ID" version="2.5">
    <display-name>SpringMVC</display-name>
    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>

    <servlet>
        <servlet-name>spring</servlet-name>
        <servlet-class>
            org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>spring</servlet-name>
        <url-pattern>*.html</url-pattern>
    </servlet-mapping>
</web-app>
<bean id="viewResolver"
    class="org.springframework.web.servlet.view.UrlBasedViewResolver">
    <property name="viewClass"
        value="org.springframework.web.servlet.view.JstlView" />
    <property name="prefix" value="/WEB-INF/jsp/" />
    <property name="suffix" value=".jsp" />
</bean>

<bean id="defaultMyDatasource" class="org.apache.commons.dbcp.BasicDataSource"
    destroy-method="close">
    <property name="driverClassName" value="${myDriverClass}" />
    <property name="url" value="${myURL}" />
    <property name="username" value="${myLogin}" />
    <property name="password" value="${myPassword}" />
</bean>
 ...