Java 运行时错误-跳过一行用户输入（扫描仪）

在我的tester文件中，我试图从用户那里接收3个输入，但是只接收到2个输入，而且程序似乎跳过了In.nextLine（）代码行。这是我的密码：

import java.util.Scanner;

public class IngredientTester
{
   public static void main(String[] args) {

        Scanner in = new Scanner(System.in);
        /*These 3 inputs work */
        System.out.println("Please enter Ingredient name.");
        String inputName = in.nextLine();
        System.out.println("Please enter Ingredient measurement type.");
        String inputType = in.nextLine();
        System.out.println("Please enter Ingredient amount");
        double inputAmount = in.nextDouble();

        Ingredient inputIngredient = new Ingredient(inputName,inputType,inputAmount);
        System.out.println(inputIngredient.getName() + "- " + inputIngredient.getAmount() + " " + inputIngredient.getMeasurement());

        System.out.println("Please enter Ingredient name.");
        inputName = in.nextLine();
                /* ^ the input above does not work, but the ones below do work */
        System.out.println("Please enter Ingredient measurement type.");
        inputType = in.nextLine();
        System.out.println("Please enter Ingredient amount");
        inputAmount = in.nextDouble();

        inputIngredient.setAmount(inputAmount); 
        inputIngredient.setName(inputName); 
        inputIngredient.setMeasurement(inputType);
        System.out.println(inputIngredient.getName() + "- " + inputIngredient.getAmount() + " " + inputIngredient.getMeasurement());
    }

}

---

问题是您正在使用：

double inputAmount = in.nextDouble();

它不仅读取您的第一个输入量，而且将回车传递到下一个

readLine

语句

解决方案是首先使用回车符：

double inputAmount = Double.parseDouble(in.nextLine());