Java中带指数的基本素因子分解
问题是: 任何正整数都可以表示为素数的唯一乘积,也称为其素因子分解。例如: 60=2^2*3*5 编写一个程序来计算正整数的素因子分解 输入:单个整数,n,其中n≥ 二, 输出:格式为“p^A*q^b*…”的字符串,其中p和q是素数,A和b是指数。如果指数为1,则应忽略它 我把其他的都记下来了,我只需要想办法把它写进“p^a*q^b*…”表格 这是我的密码:Java中带指数的基本素因子分解,java,prime-factoring,exponent,Java,Prime Factoring,Exponent,问题是: 任何正整数都可以表示为素数的唯一乘积,也称为其素因子分解。例如: 60=2^2*3*5 编写一个程序来计算正整数的素因子分解 输入:单个整数,n,其中n≥ 二, 输出:格式为“p^A*q^b*…”的字符串,其中p和q是素数,A和b是指数。如果指数为1,则应忽略它 我把其他的都记下来了,我只需要想办法把它写进“p^a*q^b*…”表格 这是我的密码: import java.util.Scanner; public class PrimeFactorization { public s
import java.util.Scanner;
public class PrimeFactorization {
public static void main(String[] args) {
// Input: A single integer, n, where n is greater than or equal to 2.
System.out.println("Please input an integer greater than or equal to two!");
System.out.println("This number will be factored.");
Scanner inputNum = new Scanner(System.in);
int toBFactored = inputNum.nextInt();
// If the input does not fit the requirements, ask again for an input.
while (toBFactored < 2) {
System.out.println("Please input an integer greater than or equal to two.");
toBFactored = inputNum.nextInt();
}
// Output: A string with the format: "p^a * q^b * ...", where p and q are
// primes, and a and b are exponents.
// Decide first if a number (testNum) is prime.
int primedecider = 0;
for (int testNum = 2; testNum < toBFactored; testNum ++) {
for (int factor = 2; factor < testNum; factor ++) {
if (testNum % factor != 0 || testNum == 2) {
// Do nothing if prime.
} else {
primedecider += 1;
// Add if composite.
}
}
// If testNum is prime, if primedecider = 0, test if testNum divides
// evenly into toBFactored.
while (primedecider == 0 && toBFactored % testNum == 0 {
System.out.print(testNum + " ");
toBFactored /= testNum;
}
}
System.out.print(toBFactored);
inputNum.close();
}
}
我对120的输出是2 3 5。如何将其转换为2^3*3*5?如果不使用System.out.println打印因子, 如果你把它们放在一个列表中, 然后,这些函数将按照您描述的方式格式化它们。 当然,这只是众多方法中的一种
private String formatFactors(List<Integer> factors) {
StringBuilder builder = new StringBuilder();
int prev = factors.get(0);
int power = 1;
int factor = prev;
for (int i = 1; i < factors.size(); ++i) {
factor = factors.get(i);
if (factor == prev) {
++power;
} else {
appendFactor(builder, prev, power);
prev = factor;
power = 1;
}
}
appendFactor(builder, factor, power);
return builder.substring(3);
}
private void appendFactor(StringBuilder builder, int factor, int power) {
builder.append(" * ").append(factor);
if (power > 1) {
builder.append("^").append(power);
}
}
你的问题实际上与素因子分解无关;您的问题是计算列表中的重复元素:不要打印到System.out,而是将因子存储在数组中,然后签出此解决方案:。