Java 按结果集从数据库中获取所需的用户和密码

1-我们通过以下方式调用require用户及其密码：

String user=usertx.getText();
    char[] password=pswdtx.getPassword();
    String pswd=String.valueOf(password);   \\here is important to put a char password in string.

此代码将仅获取所选用户的行及其行上的信息，并将其设置为（rs）

2-rs.next（）的代码：

以下是全部代码：

while(rs.next()){
     rsuser=rs.getString("NAME");      //get user and set it in rsuser.
     rspswd=rs.getString("PASSWORD");} //get password and set it in rspswd.

if ((user.equals(rsuser)) && (pswd.equals(rspswd))){  //the equevlant statement.
        JOptionPane.showMessageDialog(null, "Username and Password exist");}
        else {
            JOptionPane.showMessageDialog(null, "Please Check Username and Password ");}
        }

---

我衷心祝愿。

此代码很有可能受到SQL injection.thanx for atention@mikecatw的影响。您的问题是什么？这不是问题，而是问答。请将您的文章分成问题和答案，以分享您的知识。

while(rs.next()){
     rsuser=rs.getString("NAME");      //get user and set it in rsuser.
     rspswd=rs.getString("PASSWORD");} //get password and set it in rspswd.

if ((user.equals(rsuser)) && (pswd.equals(rspswd))){  //the equevlant statement.
        JOptionPane.showMessageDialog(null, "Username and Password exist");}
        else {
            JOptionPane.showMessageDialog(null, "Please Check Username and Password ");}
        }

private void submitActionPerformed(java.awt.event.ActionEvent evt) {                                       
    try {
        String user=usertx.getText();
        char[] password=pswdtx.getPassword();
        String pswd=String.valueOf(password);

        String rsuser=null;
        String rspswd=null;
        String Q="SELECT * FROM USERS WHERE NAME='"+user+"' AND PASSWORD='"+pswd+"'";
        rs=stmt.executeQuery(Q);

        while(rs.next()){
        rsuser=rs.getString("NAME");
        rspswd=rs.getString("PASSWORD");}
        if ((user.equals(rsuser)) && (pswd.equals(rspswd))){
        JOptionPane.showMessageDialog(null, "Username and Password exist");}
        else {
            JOptionPane.showMessageDialog(null, "Please Check Username and Password ");}
        } 
    catch (SQLException ex) {ex.printStackTrace();}`

}