Java 我应该如何为我的Connect 4程序实现横向赢算法？

我正在做一个连接4板游戏，我实现了这个横向赢算法。 不知什么原因，它似乎不起作用。 基于代码，我假设我在算法中设置的条件将在generateBoard方法中查看分配给数组的值，但事实并非如此

可能的解决办法是什么？感谢您的帮助

public static String[][] generateBoard(){
        String[][] board = new String[6][7]; //[row][column] 6 by 7
        for(int i = 0; i<board.length; i++) {
            for(int j = 0; j<board[i].length; j++) {
                if(j == 0) 
                    board[i][j] = "| |";
                else
                    board[i][j] = " |";
            }
        }
        return board;   
    }

公共静态字符串[][]生成板（）{
String[][]board=新字符串[6][7]；//[row][column]6 x 7
for（int i=0；i
//检查轮到哪个玩家
字符串颜色=（redPlayerTurn）？“R”：“Y”；
int pattern=0；//用作检测胜利者的标志
//水平检查
对于（int i=1；i
在第二个
for
，
else
分支中，是否缺少
{}
？如果缺少
{}
，每次循环运行都会将模式分配给
0
。此外，模式检查应该是
=4
。
        //Checks to see which player's turn it is
        String color = (redPlayerTurn) ? "R" : "Y";


        int pattern = 0; //Used as a flag for detecting a winner

        //HORIZONTAL Check
        for(int i = 1; i < board.length; i++) {
            String columnIndex = board[i][0];
            pattern = 1;
            for(int j = 1; j < board[i].length; j++) {
                if(!(board[i][j].contains("| |") || board[i][j].contains(" |"))) {
                    if(columnIndex == board[j][i] && pattern != 0)
                    pattern++;
                }else
                    columnIndex = board[i][j];
                    pattern = 0;
            }if(pattern == 4) {
                return true;
            }

        }

//Checks to see which player's turn it is
String color = (redPlayerTurn) ? "R" : "Y";

int pattern = 0; //Used as a flag for detecting a winner

//HORIZONTAL Check
for(int i = 1; i < board.length; i++) {
    String columnIndex = board[i][0];
    pattern = 1;
    for(int j = 1; j < board[i].length; j++) {
       if(!board[i][j].contains("|")) {
          if(columnIndex == board[j][i] && pattern != 0) {
            pattern++;
          } else {
            columnIndex = board[i][j];
            pattern = 0; // <- missing {} will assign pattern to 0
          }
       }
    }
    if(pattern >= 4) {
       return true;
    }
}