如何在java或Android中从字符串生成XML文档?
我正在尝试从Java创建一个动态生成的XML文件。这是我尝试使用的代码:如何在java或Android中从字符串生成XML文档?,java,android,xml,file,Java,Android,Xml,File,我正在尝试从Java创建一个动态生成的XML文件。这是我尝试使用的代码: try{ BufferedReader bf = new BufferedReader(new InputStreamReader(System.in)); System.out.println("how many elements: "); String str = bf.readLine(); int no = Integ
try{
BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));
System.out.println("how many elements: ");
String str = bf.readLine();
int no = Integer.parseInt(str);
System.out.println("enetr root: ");
String root = bf.readLine();
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document d1 = db.newDocument();
Element e1 = d1.createElement(root);
d1.appendChild(e1);
for (int i = 0; i < no; i++) {
System.out.println("enter element: ");
String element = bf.readLine();
System.out.println("enter data: ");
String data = bf.readLine();
Element em = d1.createElement(element);
em.appendChild(d1.createTextNode(data));
e1.appendChild(em);
}
TransformerFactory tf = TransformerFactory.newInstance();
Transformer transformer = tf.newTransformer();
DOMSource source = new DOMSource(d1);
File file = new File("src\\xml\\copy.xml");
System.out.println(file);
if(!file.exists()){
file.createNewFile();
}
OutputStream outputStream = new FileOutputStream(file);
StreamResult result = new StreamResult(outputStream);
transformer.transform(source, result);
outputStream.close();
}catch (Exception e) {
// TODO: handle exception
e.printStackTrace();
System.out.println("file not created");
}
试试看{
BufferedReader bf=新的BufferedReader(新的InputStreamReader(System.in));
System.out.println(“多少元素:”);
字符串str=bf.readLine();
int no=Integer.parseInt(str);
System.out.println(“ENTER根:”);
字符串根=bf.readLine();
DocumentBuilderFactory dbf=DocumentBuilderFactory.newInstance();
DocumentBuilder db=dbf.newDocumentBuilder();
文档d1=db.newDocument();
元素e1=d1.createElement(根);
d1.儿童(e1);
for(int i=0;i
这段代码运行得很好。但现在我有了这样一个字符串:
String xmlRecords = "<data><terminal_id>1000099999</terminal_id><merchant_id>10004444</merchant_id><merchant_info>Mc Donald's - Abdoun</merchant_info></data>";
String xmlRecords=“10000999910004444mc Donald's-Abdoun”;
我想从这个
xmlRecords
变量创建一个.xml
文件。如何执行此操作?您可以将XML字符串解析为文档,如下所示:
String xmlRecords = "<data><terminal_id>1000099999</terminal_id><merchant_id>10004444</merchant_id><merchant_info>Mc Donald's - Abdoun</merchant_info></data>";
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document d1 = builder.parse(new InputSource(new StringReader(xmlRecords)));
String xmlRecords=“10000999910004444mc Donald's-Abdoun”;
DocumentBuilderFactory工厂=DocumentBuilderFactory.newInstance();
DocumentBuilder=factory.newDocumentBuilder();
文档d1=builder.parse(新的InputSource(新的StringReader(xmlRecords));
您可以保留问题中提到的文件编写部分,只需将文档
实例的创建替换为上述代码。如果您使用XmlPullParser
,这里是另一个解决方案:
XmlPullParser parser = Xml.newPullParser();
parser.setInput(new StringReader("<your><xml><string>Hello</string></xml></your>"));
XmlPullParser=Xml.newPullParser();
setInput(新的StringReader(“Hello”);
Java1.6中的UTF-8(适用于Android)怎么样?我在字符串中获得UTF-8数据的“意外令牌”错误。