在Java中基于另一个int更改int

最近，当我遇到一些变量的问题时，我正试图为javascript自动编码

Scanner scan = new Scanner(System.in);
System.out.print("Enter x start coordinate: ");
int xCoord = scan.nextInt();
System.out.print("Enter y start coordinate: ");
int yCoord = scan.nextInt();
String more = "y";
int num1 = 0 + xCoord;
int num2 = 5 + yCoord;
int num3 = 13 + xCoord;
int num4 = 10 + yCoord;
System.out.println("ctx.moveTo(" + num1 + "," + num2 + ");"
        + "\nctx.lineTo(" + num3 + "," + num4 + ")\n"
        + "Mid Point: " + num3 + "," + num4);
System.out.print("Again?: ");
more = scan.next();
while (more.equals("y"))
{
    System.out.println("Enter a direction (above, left, right): ");
    String nextDir = scan.next();
    if (nextCube.equals("right"))
    {
        xCoord += 13;
        yCoord += 5;
    }
    else if (nextDir.equals("left"))
    {
        xCoord -= 13;
        yCoord += 5;
    }
    else if (nextDir.equals("above"))
    {
        yCoord -= 18;
    }
    System.out.println("ctx.moveTo(" + num1 + "," + num2 + ");"
        + "\nctx.lineTo(" + num3 + "," + num4 + ")\n"
        + "Mid Point: " + num3 + "," + num4);
    System.out.print("Again?: ");
    more = scan.next();
}

我发现，在询问前进方向后，xCoord和yCoord变量会发生变化，但“num”变量不会随新值一起更新。我知道在Java中依赖变量是如何工作的，我的思维过程肯定有问题，但我不知道是什么。救命啊

可能需要更新循环中的“num”变量，如：

while (more.equals("y"))
{
    ...

    // Add below codes
    num1 = 0 + xCoord;
    num2 = 5 + yCoord;
    num3 = 13 + xCoord;
    num4 = 10 + yCoord;

    System.out.println("ctx.moveTo(" + num1 + "," + num2 + ");"
        + "\nctx.lineTo(" + num3 + "," + num4 + ")\n"
        + "Mid Point: " + num3 + "," + num4);
    System.out.print("Again?: ");
    more = scan.next();
}

---

你用过调试器吗？当你说“因变量”时，听起来好像你认为当xCoord改变时num1会以某种方式动态更新？不知道为什么会出现所有的否决票。这是一个初学者的问题，基于对变量声明如何工作的基本误解，但它包含了回答该问题所需的所有元素。@user2316502非常感谢：-）