Java ANTLR-输入错误不匹配
我有一个语法,看起来像这样,由特定语言的注释和控制语句组成: 语法:Java ANTLR-输入错误不匹配,java,antlr,antlr4,Java,Antlr,Antlr4,我有一个语法,看起来像这样,由特定语言的注释和控制语句组成: 语法: grammar DD; ddlist: (ddstmt| jclcomment)+; ddstmt: dd1 | dd2 | dd3 | dd4 ; dd1: JCLBEGIN ddname DDWORD 'DUMMY'; dd2: JCLBEGIN ddname DDWORD 'DYNAM'; dd3: JCLBEGIN ddname DDWORD NAME'=' ('*'|NAM
grammar DD;
ddlist: (ddstmt| jclcomment)+;
ddstmt: dd1 | dd2 | dd3 | dd4 ;
dd1: JCLBEGIN ddname DDWORD 'DUMMY';
dd2: JCLBEGIN ddname DDWORD 'DYNAM';
dd3: JCLBEGIN ddname DDWORD NAME'=' ('*'|NAME);
dd4: JCLBEGIN ddname DDWORD '*' inlinerec INLINESTMTEND?;
inlinerec: (INLINEDATA )+ ;
fragment INLINEDATA: (~[\r\n])*;
ddname: NAME;
jclcomment: JCLCOMMENT+;
JCLCOMMENT: COMMENTBEGIN ~[\r\n]*;
DDWORD: 'DD';
JCLBEGIN: '//' ;
COMMENTBEGIN: '//*' ;
INLINESTMTEND: '/*' ;
NAME : [A-Z#] (ALPHA | NUMBER | SPECIALCHARS)*;
NUMBER: [0-9];
ALPHA: [A-Z];
SPECIALCHARS: '#' | '@' | '$';
STRING
: '\'' (~[\r\n"])* '\''
| '"' (~[\r\n"])* '"'
;
WS : [ \r\n] -> channel(HIDDEN);
我的意见是:
//SYSIN DD *
SORT FIELDS=COPY
INCLUDE COND
/*
//SYSPRINT DD SYSOUT=*
//* Comment line #1
//* Comment line #2
//SYSOUT DD SYSOUT=*
//CEEDUMP DD SYSOUT=*
//* Comment line #3
//SYSUDUMP DD SYSOUT=A
使用AntlrWorks对输入运行此语法时,出现以下错误:
line 2:0 mismatched input 'SORT' expecting INLINEDATA
如何解决此错误?1)空白规则生成大量令牌:
$ echo $CLASSPATH
.:/usr/local/lib/antlr-4.6-complete.jar
$ alias grun
alias grun='java org.antlr.v4.gui.TestRig'
$ grun DD ddlist -tokens jcl.txt
[@6,11:12='DD',<'DD'>,1:11]
[@7,13:13=' ',<WS>,channel=1,1:13]
[@8,14:14=' ',<WS>,channel=1,1:14]
[@9,15:15='*',<'*'>,1:15]
[@10,16:16=' ',<WS>,channel=1,1:16]
[@11,17:17=' ',<WS>,channel=1,1:17]
[@12,18:18=' ',<WS>,channel=1,1:18]
[@13,19:19=' ',<WS>,channel=1,1:19]
[@14,20:20=' ',<WS>,channel=1,1:20]
[@15,21:21=' ',<WS>,channel=1,1:21]
[@16,22:22=' ',<WS>,channel=1,1:22]
2) 您没有提到编译语法时出现的重要错误消息:
warning(125): DD.g4:12:12: implicit definition of token INLINEDATA in parser
在解析器中使用未定义的标记就好像您有一个lexer规则:
INLINEDATA : 'INLINEDATA' ;
这是一个字符串常量。因此,解析器规则
dd4: JCLBEGIN ddname DDWORD '*' inlinerec INLINESTMTEND?;
意思是:我希望输入流是:
//{a name} DD * 'INLINEDATA'
但投入是:
//SYSIN DD * SORT
这就是信息
line 2:0 mismatched input 'SORT' expecting INLINEDATA
3) 我对此类作业控制语句的语法:
grammar JCL;
/* Parsing JCL, ignoring inline sysin. */
jcl
: jcl_card+ // good old punched cards :-)
;
jcl_card
: dd_statement
| COMMENT
;
dd_statement
: '//' NAME 'DD' file_type ( NL | EOF )
;
file_type
: 'DUMMY'
| 'DYNAM'
| NAME '=' ( '*' | NAME )
| '*' NL inline_sysin
;
inline_sysin
: NON_JCL_CARD* END_OF_FILE
;
NAME : [A-Z#] ( LETTER | DIGIT | SPECIAL_CHARS )* ;
COMMENT : '//*' .*? ( NL | EOF ) ;
END_OF_FILE : '/' {getCharPositionInLine() == 1}? '*' ;
NON_JCL_CARD : ~'/' {getCharPositionInLine() == 1}? .*? ( NL | EOF ) ;
STRING : '\'' .*? '\'' | '"' .*? '"' ;
NL : [\r\n] ;
WS : [ \t]+ -> skip ; // or -> channel(HIDDEN) to keep white space tokens
fragment DIGIT : [0-9] ;
fragment LETTER : [A-Z] ;
fragment SPECIAL_CHARS : '#' | '@' | '$' ;
输入
//SYSIN DD *
SORT FIELDS=COPY
INCLUDE COND
any other program input @ $ ! & %
/*
//SYSPRINT DD SYSOUT=*
//* Comment line #1
//* Comment line #2
//SYSOUT DD SYSOUT=*
//SYSOUT DD DUMMY
//SYSIN DD *
/* not end of input
/*
它给
$ grun JCL jcl -tokens jcl.txt
[@0,0:1='//',<'//'>,1:0]
[@1,2:6='SYSIN',<NAME>,1:2]
[@2,11:12='DD',<'DD'>,1:11]
[@3,15:15='*',<'*'>,1:15]
[@4,21:21='\n',<NL>,1:21]
[@5,22:38='SORT FIELDS=COPY\n',<NON_JCL_CARD>,2:0]
[@6,39:51='INCLUDE COND\n',<NON_JCL_CARD>,3:0]
[@7,52:85='any other program input @ $ ! & %\n',<NON_JCL_CARD>,4:0]
[@8,86:87='/*',<END_OF_FILE>,5:0]
[@9,106:106='\n',<NL>,5:20]
...
@17,131:161='//* Comment line #1 \n',<COMMENT>,7:0]
...
[@31,232:233='//',<'//'>,11:0]
[@32,234:238='SYSIN',<NAME>,11:2]
[@33,243:244='DD',<'DD'>,11:11]
[@34,247:247='*',<'*'>,11:15]
[@35,253:253='\n',<NL>,11:21]
[@36,254:278=' /* not end of input \n',<NON_JCL_CARD>,12:0]
[@37,279:280='/*',<END_OF_FILE>,13:0]
[@38,281:280='<EOF>',<EOF>,13:2]
如果解析器规则dd4产生冲突,那么单独为dd4编写一个单独的语法,然后再编写主语法有意义吗?如果您有任何疑问,请与我们分享最佳实践。谢谢您的回答。让我尝试您的解决方案并更新您。当我使用Antlrworks2运行语法时,我收到了此错误
第1:22行无关输入'\n'预期{END_OF_FILE,NON_JCL_CARD}
。我更改了NL:[\r\n]代码>到NL:'\r'\n'代码>而且它就像一个魔咒,如果你看看我的原始语法,我可以选择INLINESTMTEND
。因此,我将把解决方案语法中的END\u OF_FILE
设置为可选,并尝试在没有NL标记的情况下重写语法。语法必须与输入匹配,反之亦然。所以抱怨我们有太多的评论,并建议继续聊天,但我并不总是在线。我已经删除了一些评论,你可以这样做,我想未来的读者对此并不感兴趣。
$ grun JCL jcl -tokens jcl.txt
[@0,0:1='//',<'//'>,1:0]
[@1,2:6='SYSIN',<NAME>,1:2]
[@2,11:12='DD',<'DD'>,1:11]
[@3,15:15='*',<'*'>,1:15]
[@4,21:21='\n',<NL>,1:21]
[@5,22:38='SORT FIELDS=COPY\n',<NON_JCL_CARD>,2:0]
[@6,39:51='INCLUDE COND\n',<NON_JCL_CARD>,3:0]
[@7,52:85='any other program input @ $ ! & %\n',<NON_JCL_CARD>,4:0]
[@8,86:87='/*',<END_OF_FILE>,5:0]
[@9,106:106='\n',<NL>,5:20]
...
@17,131:161='//* Comment line #1 \n',<COMMENT>,7:0]
...
[@31,232:233='//',<'//'>,11:0]
[@32,234:238='SYSIN',<NAME>,11:2]
[@33,243:244='DD',<'DD'>,11:11]
[@34,247:247='*',<'*'>,11:15]
[@35,253:253='\n',<NL>,11:21]
[@36,254:278=' /* not end of input \n',<NON_JCL_CARD>,12:0]
[@37,279:280='/*',<END_OF_FILE>,13:0]
[@38,281:280='<EOF>',<EOF>,13:2]
$ grun JCL jcl -gui jcl.txt