Java 如何模拟Junit的内部方法调用

我有以下资料：

public class A{

  private SOAPMessage msg;
  SOAPMessage getmSOAP()
    {
        return msg;
    }

    public Map<String,String> getAllProfiles(String type) throws SOAPException
    {

        NodeList profilesTypes = getmsoapResponse().getSOAPBody().getElementsByTagName("profileType");

        ...
    }
}

运行B：

m_mock = spy(new A())
doReturn(m_SOAPRespones).when(m_mock ).getmsoapResponse();

两者都不起作用，我做错了什么

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运行B在最后工作，有一个小错误

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建议的答案也很有效

您只遗漏了一件事：您还需要在此处模拟

.getSoapBody（）

的结果

对以下类别进行假设；只需替换为适当的类；还要注意，我尊重Java命名约定，您也应该：

final A mock = spy(new A());

final SOAPResponse response = mock(SOAPResponse.class);
final SOAPBody body = mock(SOAPBody.class);

// Order does not really matter, of course, but bottom up makes it clearer
// SOAPBody
when(body.whatever()).thenReturn(whatIsNeeded);

// SOAPResponse
when(response.getSoapBody()).thenReturn(body);

// Your A class
when(mock.getSoapResponse()).thenReturn(response);
when(mock.getAllProfiles("")).thenCallRealMethod();

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简而言之：您需要模拟链中的所有元素。请务必遵循Java命名约定，这使以后阅读您的代码的人更容易；）

你的第二种方法看起来不错。当你说它“不起作用”时，你的确切意思是什么？你哪里对：）有一个bug:P

final A mock = spy(new A());

final SOAPResponse response = mock(SOAPResponse.class);
final SOAPBody body = mock(SOAPBody.class);

// Order does not really matter, of course, but bottom up makes it clearer
// SOAPBody
when(body.whatever()).thenReturn(whatIsNeeded);

// SOAPResponse
when(response.getSoapBody()).thenReturn(body);

// Your A class
when(mock.getSoapResponse()).thenReturn(response);
when(mock.getAllProfiles("")).thenCallRealMethod();