Java 从谷歌地图的坐标中获取地址

我正在尝试一个位置应用程序，目前我在标记上有该位置的坐标。现在，我如何从已经存在的坐标中获得位置的名称

我的代码：

//search add address
private void geoLocate() {
    Log.d( TAG, "geoLocate: geolocating" );
    String searchString = mSearchText.getText().toString();

    Geocoder geocoder = new Geocoder( MapActivity.this );

    List<Address> list = new ArrayList<>();

    try {
        list = geocoder.getFromLocationName( searchString, 1 );
    } catch (IOException e) {
        Log.e( TAG, "geoLocate: IOException" + e.getMessage() );
    }

    if (list.size() > 0) {
        Address address = list.get( 0 );
        Log.d( TAG, "geoLocate: found a location:  " + address.toString() );
        moveCamera( new LatLng( address.getLatitude(), address.getLongitude() ), DEFAULT_ZOOM,address.getAddressLine( 0 ) );
    }
}

---

您可以使用下面的代码获取基于latlong的地址

try {
        Geocoder geocoder;
        String city=null;
        List<Address> yourAddresses;
        geocoder = new Geocoder(this, Locale.getDefault());
        yourAddresses = geocoder.getFromLocation(yourLatitude, yourLongitude, 1);


    final String yourAddress = yourAddresses.get(0).getAddressLine(0);
    if (yourAddresses != null && yourAddresses.size() > 0) {
        android.location.Address address = yourAddresses.get(0);
        @SuppressWarnings("MismatchedQueryAndUpdateOfStringBuilder") StringBuilder sb = new StringBuilder();
        for (int i = 0; i < address.getMaxAddressLineIndex(); i++) {
            sb.append(address.getAddressLine(i)).append("\n");
        }
        city = address.getLocality();
        Log.d("city", "onCreate: "+city);
    }

    } catch (IOException e) {
        e.printStackTrace();
    }

试试看{
地理编码器；
字符串city=null；
列出你的地址；
geocoder=新的geocoder（这个，Locale.getDefault（））；
yourAddresses=geocoder.getFromLocation（yourLatitude，yourLatitude，1）；
最后一个字符串yourAddress=yourAddresses.get（0）.getAddressLine（0）；
if（yourAddresses！=null&&yourAddresses.size（）>0）{
android.location.Address=yourAddresses.get（0）；
@SuppressWarnings（“不匹配的QueryAndUpdateOfStringBuilder”）StringBuilder sb=new StringBuilder（）；
对于（int i=0；i

可能重复：您根据自己的代码提出了一个相反的问题。您想做的事情可能重复。你能解释清楚吗？例如：我有一个坐标：40.657052:73.990700 convert->>=纽约布鲁克林

try {
        Geocoder geocoder;
        String city=null;
        List<Address> yourAddresses;
        geocoder = new Geocoder(this, Locale.getDefault());
        yourAddresses = geocoder.getFromLocation(yourLatitude, yourLongitude, 1);


    final String yourAddress = yourAddresses.get(0).getAddressLine(0);
    if (yourAddresses != null && yourAddresses.size() > 0) {
        android.location.Address address = yourAddresses.get(0);
        @SuppressWarnings("MismatchedQueryAndUpdateOfStringBuilder") StringBuilder sb = new StringBuilder();
        for (int i = 0; i < address.getMaxAddressLineIndex(); i++) {
            sb.append(address.getAddressLine(i)).append("\n");
        }
        city = address.getLocality();
        Log.d("city", "onCreate: "+city);
    }

    } catch (IOException e) {
        e.printStackTrace();
    }