Java 无法使用外部jar文件'；父项目中的自动连线类

我的项目可以独立使用自动连线选项，我从这个项目创建了一个jar文件。问题是在我将这个jar添加到父项目之后出现的，当我尝试在父项目中使用外部jar文件的类时，我遇到了类似“线程中的异常”main“java.lang.NullPointerException…”的错误

但若我不在我的外部jar文件中使用autowired选项并手动编写代码填充上下文，那个么外部jar文件就可以与我的父项目配合使用

带有自动连线类的外部Jar文件

public class UserService {


@Autowired 
UserRepository userRepository;

@Autowired
Movie2Repository movieRepository;

@Autowired
PersonRepository personRepository;


ConfigurableApplicationContext context;
public UserService(){
    // context = new ClassPathXmlApplicationContext("META-INF/spring/application-context.xml");
}


public void closeApp(){

    //context.close();
}

public void  insert(){
     //userRepository = context.getBean(UserRepository.class);
     System.out.println("user vvvv");
     User u = new User();
     u.firstname="dede";
     userRepository.save(u);
     System.out.println("user eklendi");

外部jar文件中的ApplicationContext文件

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:neo4j="http://www.springframework.org/schema/data/neo4j"
xmlns:mongo="http://www.springframework.org/schema/data/mongo"
xmlns:aop="http://www.springframework.org/schema/aop" 
xmlns:context="http://www.springframework.org/schema/context"
xmlns:jee="http://www.springframework.org/schema/jee" 
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xsi:schemaLocation="http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd
    http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
    http://www.springframework.org/schema/data/mongo http://www.springframework.org/schema/data/mongo/spring-mongo.xsd
    http://www.springframework.org/schema/data/neo4j http://www.springframework.org/schema/data/neo4j/spring-neo4j.xsd
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/data/jpa http://www.springframework.org/schema/data/jpa/spring-jpa-1.0.xsd
    http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">

<!-- JPA -->

<context:property-placeholder
    location="/META-INF/spring/database.properties" />

<import resource="/database.xml"/>


<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>

 <bean id="jpaVendorAdapter"
    class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
    <property name="showSql" value="false" />
    <property name="database" value="MYSQL" />
</bean>


<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <property name="dataSource" ref="dataSource" />
    <property name="persistenceUnitName" value="persistenceUnit" />
    <property name="jpaVendorAdapter" ref="jpaVendorAdapter" />
</bean>

<jpa:repositories base-package="org.springframework.data.example.jpa" />

package abcdef;
import org.springframework.data.example.*; 
import org.springframework.data.example.jpa.UserService;
import org.springframework.data.example.jpa.UserService2;

public class abcde {

        public static void main(String[] args) {
            // TODO Auto-generated method stub
            UserService u= new UserService();
            u.insert();

        }


}

父项目中的应用程序上下文文件

<!-- JPA -->

<context:property-placeholder
    location="/META-INF/spring/database.properties" />

<import resource="/database.xml"/>

<import resource="classpath*:/META-INF/spring/*.xml" />


<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>

 <bean id="jpaVendorAdapter"
    class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
    <property name="showSql" value="false" />
    <property name="database" value="MYSQL" />
</bean>


<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <property name="dataSource" ref="dataSource" />
    <property name="persistenceUnitName" value="persistenceUnit" />
    <property name="jpaVendorAdapter" ref="jpaVendorAdapter" />
</bean>

<jpa:repositories base-package="org.springframework.data.example.jpa" />

---

很简单。您的

UserService

没有连接，因为您使用

new

创建了它，并且没有从spring上下文中检索到它

public class abcde {

    public static void main(String[] args) {
        ApplicationContext ctx = new ClassPathXmlApplicationContext("META-INF/spring/application-context.xml");
        UserService u = ctx.getBean("userService");
        u.insert();

    }
}

或者类似的

---

然而，您的

UserService

缺少其xml配置或

@组件，这取决于spring实际连接它的配置。您可能应该创建从外部jar导入的本地spring配置文件。
非常简单。您的
UserService
没有连接，因为您使用
new
创建了它，并且没有从spring上下文中检索到它

public class abcde {

    public static void main(String[] args) {
        ApplicationContext ctx = new ClassPathXmlApplicationContext("META-INF/spring/application-context.xml");
        UserService u = ctx.getBean("userService");
        u.insert();

    }
}

或者类似的

然而，您的
UserService
缺少其xml配置或
@组件，这取决于spring实际连接它的配置。您可能应该创建从外部jar导入的本地spring配置文件