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Java Spring安全,始终重定向到登录页面_Java_Spring_Hibernate_Spring Mvc_Weblogic11g - Fatal编程技术网

Java Spring安全,始终重定向到登录页面

Java Spring安全,始终重定向到登录页面,java,spring,hibernate,spring-mvc,weblogic11g,Java,Spring,Hibernate,Spring Mvc,Weblogic11g,我有一个严重的问题。。。 我试图在WebLogic11g上创建一个应用程序,使用Spring3、Hibernate3和AngularJS。 两天来,我一直很难让我的应用程序正常运行。 最后,我终于成功了 但是,问题是当我对自己进行身份验证时,我在应用程序上导航,在每个页面上, spring security在登录页面上重定向我。。。我真的不知道为什么 Web.xml: <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance

我有一个严重的问题。。。 我试图在WebLogic11g上创建一个应用程序,使用Spring3、Hibernate3和AngularJS。 两天来,我一直很难让我的应用程序正常运行。 最后,我终于成功了

但是,问题是当我对自己进行身份验证时,我在应用程序上导航,在每个页面上, spring security在登录页面上重定向我。。。我真的不知道为什么

Web.xml:

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:jsp="http://java.sun.com/xml/ns/javaee/jsp" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
  <servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
      <param-name>contextConfigLocation</param-name>
      <param-value>/WEB-INF/spring/spring.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>

  <servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>

  <listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
  </listener>
  <listener>
    <listener-class>com.bla.Init</listener-class>
</listener>

  <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
            /WEB-INF/spring/spring.xml
        </param-value>
  </context-param>

  <filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
  </filter>
  <filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
  </filter-mapping>
  <filter>
    <filter-name>encodingFilter</filter-name>
    <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
    <init-param>
      <param-name>encoding</param-name>
      <param-value>UTF-8</param-value>
    </init-param>
    <init-param>
      <param-name>forceEncoding</param-name>
      <param-value>true</param-value>
    </init-param>
  </filter>
  <filter-mapping>
    <filter-name>encodingFilter</filter-name>
    <servlet-name>dispatcher</servlet-name>
  </filter-mapping>
  <jsp-config>
    <jsp-property-group>
      <url-pattern>*.jsp</url-pattern>
      <page-encoding>UTF-8</page-encoding>
      <trim-directive-whitespaces>true</trim-directive-whitespaces>
    </jsp-property-group>
  </jsp-config>
</web-app>

调度员
org.springframework.web.servlet.DispatcherServlet
上下文配置位置
/WEB-INF/spring/spring.xml
1.
调度员
/
org.springframework.web.context.ContextLoaderListener
com.bla.Init
上下文配置位置
/WEB-INF/spring/spring.xml
springSecurityFilterChain
org.springframework.web.filter.DelegatingFilterProxy
springSecurityFilterChain
/*
编码滤波器
org.springframework.web.filter.CharacterEncodingFilter
编码
UTF-8
强制编码
真的
编码滤波器
调度员
*.jsp
UTF-8
真的
Spring.xml

<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
                           http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
                           http://www.springframework.org/schema/context http://www.springframework.org/schema/task/spring-context-3.0.xsd">

    <!-- Basic Configurations -->
    <context:annotation-config/>

    <context:component-scan base-package="test.model"/>
    <context:component-scan base-package="test.repository"/>
    <context:component-scan base-package="test.service"/>
    <context:component-scan base-package="test.controller"/>

    <!-- SpringMVC -->
    <import resource="spring-mvc.xml"/>

    <!-- SpringData -->
    <import resource="spring-jpa.xml"/>

    <!-- SpringSecurity -->
    <import resource="spring-security.xml"/>
</beans>

spring security.xml

<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:security="http://www.springframework.org/schema/security"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
       http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security.xsd">

    <security:global-method-security secured-annotations="enabled" />

    <security:http auto-config="true" use-expressions="true" access-denied-page="/login?error=403">

        <security:intercept-url pattern="/" access="permitAll" />
        <security:intercept-url pattern="/protected/**" access="isFullyAuthenticated()" />

        <security:form-login login-page="/login" authentication-failure-url="/login?error=403" default-target-url="/protected/home" />

        <security:logout invalidate-session="true" logout-success-url="/login" logout-url="/logout" />
    </security:http>

    <security:authentication-manager>
        <security:authentication-provider>
            <security:jdbc-user-service
                    data-source-ref="myRapportDataSource"
                    users-by-username-query="select nni, password, enabled from system_user where nni = ?"
                    authorities-by-username-query="select u.nni as login, u.user_role as role from system_user u where u.nni = ?" />
        </security:authentication-provider>
    </security:authentication-manager>
</beans>

我还添加了spring mvc.xml

<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:mvc="http://www.springframework.org/schema/mvc"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
                           http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">

    <mvc:annotation-driven/>
    <mvc:default-servlet-handler/>

    <!-- Login Interceptor -->
    <mvc:interceptors>
        <mvc:interceptor>
            <mvc:mapping path="/protected/**"/>
            <bean class="gram.interceptor.LoginInterceptor"/>
        </mvc:interceptor>
        <!-- workaround to fix IE8 problem -->
        <bean id="webContentInterceptor"
              class="org.springframework.web.servlet.mvc.WebContentInterceptor">
            <property name="cacheSeconds" value="0"/>
            <property name="useExpiresHeader" value="true"/>
            <property name="useCacheControlHeader" value="true"/>
            <property name="useCacheControlNoStore" value="true"/>
        </bean>
    </mvc:interceptors>
</beans>

起初,这个应用程序在Tomcat6上运行良好,但我必须在WebLogic10.3.6上迁移它

有什么想法吗?我几乎绝望了

非常感谢各位来看看我的问题


只有与
/
匹配的URL才具有
权限
访问权限。所以你需要的实际上是:


带有


只有与
/
匹配的URL才具有
权限
访问权限。所以你需要的实际上是:



试试
pattern=“/**”access=“permitAll”
。我的上帝sp00m,你救了我!我只是。。。非常感谢你!试试
pattern=“/**”access=“permitAll”
。我的上帝sp00m,你救了我!我只是。。。非常感谢你!