Warning: file_get_contents(/data/phpspider/zhask/data//catemap/5/fortran/2.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
打开url连接并等待完成url java的加载_Java_Connection - Fatal编程技术网

打开url连接并等待完成url java的加载

打开url连接并等待完成url java的加载,java,connection,Java,Connection,我有以下代码。我想在加载完url后获取url。如何连接以等待先完成加载? 先谢谢你 URL u = new URL("http://google.com/search?sourceid=navclient&btnI=1&q=" + jTextField1.getText().toString()); HttpURLConnection con = (HttpURLConnection) u.openConnection(); 检查con.getResponseCode()==2

我有以下代码。我想在加载完url后获取url。如何连接以等待先完成加载? 先谢谢你

URL u = new URL("http://google.com/search?sourceid=navclient&btnI=1&q=" + jTextField1.getText().toString());
HttpURLConnection con = (HttpURLConnection) u.openConnection();

检查con.getResponseCode()==200..如何使用它?你能帮忙吗。它试图用if语句检查它。比如if(con.getResponseCode()==200),但是我必须让连接等待以获取响应代码。您能提供更多帮助吗?请参阅此答案以获取帮助
HttpURLConnection ex1 = (HttpURLConnection) u.openConnection();
ex1.setChunkedStreamingMode(7000); // enable chunked streaming mode before connecting  to server.