Java 有效地替换AntlInputStream（ANTLRStringStream）文件输入中的字符串或字符

如中所述，对于可能在字符串文字中包含字符串文字的语言，我有一些问题，例如： START: "img src="test.jpg""
我的问题是：

• 哪种模式是正确的？重要的是，可以在多行上定义字符串文字，例如“aaaa”\n“bbb”，但始终以“\n:END\u START”行结束。我的愿望是取得以下结果：

---

解决第一个问题
我必须对模式标志pattern.DOTALL使用非贪婪方法：

Pattern pattern = Pattern.compile("(START:\s\")(.+)(\"\n:END_START)", Pattern.DOTALL);
Pattern pattern = Pattern.compile("(START:\\s\")(.+?)(\"\\n:END_START)", Pattern.DOTALL);
Pattern pattern = Pattern.compile("(START:\\s\")(.+?)(\"\\n:END_START)", Pattern.DOTALL);
守则：

 public static void main(String[] args) {

    try{
        FileInputStream fis = new FileInputStream("src/file.txt");
        String preparedCode = preparingCode(fis);

        ANTLRStringStream in = new ANTLRStringStream(preparedCode);

        TestLexer lex = new TestLexer(in);
        CommonTokenStream tokens = new CommonTokenStream(lex);
        TestParser parser = new TestParser(tokens);

        parser.rule();
    }catch(IOException ex){
        ex.printStackTrace();
    } catch (RecognitionException e) {
        System.out.println(e.getMessage());
        System.exit(0);
    }
}

static String preparingCode(FileInputStream input){
    DataInputStream data = new DataInputStream(input);
    StringBuilder oldCode = new StringBuilder();
    StringBuffer newCode = new StringBuffer(oldCode.length());

    Pattern pattern = Pattern.compile("(START:\\s\")(.+?)(\"\\n:END_START)", Pattern.DOTALL);
    String strLine;
    try{
      while ((strLine = data.readLine()) != null)   
          oldCode.append(strLine + "\n");
    }
    catch(IOException ex){
      ex.printStackTrace();
    }

    Matcher matcher = pattern.matcher(oldCode);

    while (matcher.find()) {
        System.out.println("++++"+matcher.group(2));
      //eliminate quotes inside a string literal
      String stringLiteral = matcher.group(2).replaceAll("\"", "'");

      String replace = matcher.group(1) + stringLiteral + matcher.group(3);
      matcher.appendReplacement(newCode, Matcher.quoteReplacement(replace));
    }
    matcher.appendTail(newCode);

    System.out.println(newCode);

    return newCode.toString();
}

那么有没有其他方法来解决这个问题呢？
哦。。。您是对的，在某些情况下，两个字符串在多行中@关于你的最后一个问题，我编辑了我的原始问题。我希望它现在更清楚。我自己解决了第一个问题。
Pattern pattern = Pattern.compile("(START:\s\")(.+)(\"\n:END_START)", Pattern.DOTALL);
Pattern pattern = Pattern.compile("(START:\\s\")(.+?)(\"\\n:END_START)", Pattern.DOTALL);
Pattern pattern = Pattern.compile("(START:\\s\")(.+?)(\"\\n:END_START)", Pattern.DOTALL);
 public static void main(String[] args) {

    try{
        FileInputStream fis = new FileInputStream("src/file.txt");
        String preparedCode = preparingCode(fis);

        ANTLRStringStream in = new ANTLRStringStream(preparedCode);

        TestLexer lex = new TestLexer(in);
        CommonTokenStream tokens = new CommonTokenStream(lex);
        TestParser parser = new TestParser(tokens);

        parser.rule();
    }catch(IOException ex){
        ex.printStackTrace();
    } catch (RecognitionException e) {
        System.out.println(e.getMessage());
        System.exit(0);
    }
}

static String preparingCode(FileInputStream input){
    DataInputStream data = new DataInputStream(input);
    StringBuilder oldCode = new StringBuilder();
    StringBuffer newCode = new StringBuffer(oldCode.length());

    Pattern pattern = Pattern.compile("(START:\\s\")(.+?)(\"\\n:END_START)", Pattern.DOTALL);
    String strLine;
    try{
      while ((strLine = data.readLine()) != null)   
          oldCode.append(strLine + "\n");
    }
    catch(IOException ex){
      ex.printStackTrace();
    }

    Matcher matcher = pattern.matcher(oldCode);

    while (matcher.find()) {
        System.out.println("++++"+matcher.group(2));
      //eliminate quotes inside a string literal
      String stringLiteral = matcher.group(2).replaceAll("\"", "'");

      String replace = matcher.group(1) + stringLiteral + matcher.group(3);
      matcher.appendReplacement(newCode, Matcher.quoteReplacement(replace));
    }
    matcher.appendTail(newCode);

    System.out.println(newCode);

    return newCode.toString();
}