Java 如何实现JPQL查询?

Java 如何实现JPQL查询?,java,sql,jpa,jpql,Java,Sql,Jpa,Jpql,我在PostgreSQL中有工作查询: select s.id, s.seat_number as available_seat, s.row_number as available_row, rm.room_name as screening_room from seats s join rooms rm on rm.id=s.room_id left join ( select r.seat_id from reserved_seats r

我在PostgreSQL中有工作查询:

select s.id, s.seat_number as available_seat, s.row_number as available_row, rm.room_name as screening_room
from seats s
         join rooms rm on rm.id=s.room_id
         left join (
    select r.seat_id from reserved_seats r
                              join reservations  res on res.id=r.reservation_id AND res.screening_id = 3 ) res on res.seat_id=s.id
where res.seat_id is null AND s.room_id=3
ORDER BY s.id;
但是我在把它翻译成JPA查询语言时会出错

我可以在JPQL中使用嵌套选择吗


答案是使用本机查询

@Query(value =
            "SELECT s.id seatId, s.seat_number availableSeat, " +
                    "s.row_number availableRow, rm.name screeningRoom \n" +
                    "FROM seats s\n" +
                    "JOIN rooms rm on rm.id=s.room_id\n" +
                    "   LEFT JOIN (\n" +
                    "       SELECT r.seat_id FROM reserved_seats r\n" +
                    "       JOIN reservations res ON res.id=r.reservation_id " +
                    "       AND res.screening_id = :screeningId) res ON res.seat_id=s.id\n" +
                    "WHERE res.seat_id IS NULL AND s.room_id=:roomId AND s.row_number=:rowNumber\n" +
                    "ORDER BY s.id;", nativeQuery = true)
@Query(value =
            "SELECT s.id seatId, s.seat_number availableSeat, " +
                    "s.row_number availableRow, rm.name screeningRoom \n" +
                    "FROM seats s\n" +
                    "JOIN rooms rm on rm.id=s.room_id\n" +
                    "   LEFT JOIN (\n" +
                    "       SELECT r.seat_id FROM reserved_seats r\n" +
                    "       JOIN reservations res ON res.id=r.reservation_id " +
                    "       AND res.screening_id = :screeningId) res ON res.seat_id=s.id\n" +
                    "WHERE res.seat_id IS NULL AND s.room_id=:roomId AND s.row_number=:rowNumber\n" +
                    "ORDER BY s.id;", nativeQuery = true)

答案是使用本机查询

@Query(value =
            "SELECT s.id seatId, s.seat_number availableSeat, " +
                    "s.row_number availableRow, rm.name screeningRoom \n" +
                    "FROM seats s\n" +
                    "JOIN rooms rm on rm.id=s.room_id\n" +
                    "   LEFT JOIN (\n" +
                    "       SELECT r.seat_id FROM reserved_seats r\n" +
                    "       JOIN reservations res ON res.id=r.reservation_id " +
                    "       AND res.screening_id = :screeningId) res ON res.seat_id=s.id\n" +
                    "WHERE res.seat_id IS NULL AND s.room_id=:roomId AND s.row_number=:rowNumber\n" +
                    "ORDER BY s.id;", nativeQuery = true)
@Query(value =
            "SELECT s.id seatId, s.seat_number availableSeat, " +
                    "s.row_number availableRow, rm.name screeningRoom \n" +
                    "FROM seats s\n" +
                    "JOIN rooms rm on rm.id=s.room_id\n" +
                    "   LEFT JOIN (\n" +
                    "       SELECT r.seat_id FROM reserved_seats r\n" +
                    "       JOIN reservations res ON res.id=r.reservation_id " +
                    "       AND res.screening_id = :screeningId) res ON res.seat_id=s.id\n" +
                    "WHERE res.seat_id IS NULL AND s.room_id=:roomId AND s.row_number=:rowNumber\n" +
                    "ORDER BY s.id;", nativeQuery = true)

阅读关于jpql的文章。Ist不同于sql。它适用于对象而不是表。不要质疑不必要的图像。您的复制粘贴也适用于文本。@Kayaman将其用于显示我的错误…@Jens读取我的查询,其用于对象