Java Spring rest post服务将空值作为变量发送
我是SpringMVC的新手,我正在公开REST服务。我的Java Spring rest post服务将空值作为变量发送,java,json,spring,rest,null,Java,Json,Spring,Rest,Null,我是SpringMVC的新手,我正在公开REST服务。我的GET服务工作正常,但来自邮递员的POST呼叫将空null值作为字段发送 下面是使用各种形式的POST注释的REST服务示例。在过去的三天里,我一直在做这件事。请帮忙 package com.cgi.ehr.rest; import javax.ejb.EJB; import javax.ws.rs.Produces; import javax.ws.rs.core.MediaType; import org.springframewo
GET
服务工作正常,但来自邮递员的POST
呼叫将空null
值作为字段发送
下面是使用各种形式的POST
注释的REST服务示例。在过去的三天里,我一直在做这件事。请帮忙
package com.cgi.ehr.rest;
import javax.ejb.EJB;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.web.bind.annotation.RestController;
import com.cgi.ehr.services.dao.UserDetailsDAO;
import com.cgi.test.dto.InputDto;
@RestController
@RequestMapping("/bookmarks")
public class CheckingService {
@EJB
UserDetailsDAO userDetailsDAO;
@RequestMapping(value = "/bookmark", method = RequestMethod.GET)
public InputDto testM() {
return userDetailsDAO.testMethod();
}
@RequestMapping(value = "/testM2", method = RequestMethod.GET,headers="Accept=*/*", produces="application/json")
//@Produces(MediaType.APPLICATION_JSON)
public InputDto testM2() {
InputDto d = new InputDto("1","2");
return d;
}
@RequestMapping(value = "/bookmarkPost", method = RequestMethod.POST, consumes = MediaType.APPLICATION_JSON)
@Produces(MediaType.APPLICATION_JSON)
//@ResponseBody
public InputDto testPost(InputDto inputDto) {
String age = inputDto.getTestAge();
String name = inputDto.getTestname();
InputDto dto = new InputDto();
dto.setTestAge(age + "gotback");
dto.setTestname(inputDto.getTestname() + "gotback");
return dto;
}
@RequestMapping(value = "/bookmarkPost1", method = RequestMethod.POST)
public InputDto testPost1(InputDto inputDto) {
String age = inputDto.getTestAge();
String name = inputDto.getTestname();
InputDto dto = new InputDto();
dto.setTestAge(age + "gotback");
dto.setTestname(inputDto.getTestname() + "gotback");
return dto;
}
@RequestMapping(value = "/person", method = RequestMethod.POST, headers = "Accept=application/xml, application/json")
public @ResponseBody InputDto addPerson(@RequestBody InputDto inputDto) {
return inputDto;
}
}
`
package com.cgi.test.dto;
import java.io.Serializable;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class InputDto implements Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
private String testname;
private String testAge;
public String getTestname() {
return testname;
}
public void setTestname(String testname) {
this.testname = testname;
}
public String getTestAge() {
return testAge;
}
public void setTestAge(String testAge) {
this.testAge = testAge;
}
public InputDto() {
super();
}
public InputDto(String testname, String testAge) {
this.testname = testname;
this.testAge = testAge;
}
}
您的testPost方法应该如下所示。现在,您可以使用相同的请求使用邮递员
@RequestMapping(value = "/bookmarkPost", method = RequestMethod.POST, produces = MediaType.APPLICATION_JSON_VALUE,consumes = MediaType.APPLICATION_JSON_VALUE)
public @ResponseBody InputDto testPost(@RequestBody InputDto inputDto) {
String age = inputDto.getTestAge();
String name = inputDto.getTestname();
InputDto dto = new InputDto();
dto.setTestAge(age + "gotback");
dto.setTestname(name + "gotback");
return dto;
}
在
InputDto
类中,设置程序正确地设置了实例变量this.testXxx
public void setTestname(String testname) {
this.testname = testname;
}
但是,getter不会返回此实例变量。请注意您缺少的此项。
以下内容应该可以修复您当前的问题,然后应用于两个getter
public String getTestAge() {
return this.testAge;
}
抱歉,伙计们…代码一直在工作,我在postman中提交帖子数据时犯了一个非常愚蠢的错误(我选择了错误的标签,没有在“正文”下发送它)。。。我在这上面浪费了3天!!!!。。无论如何,再次感谢@abaghelinput json:{“testname”:“myname”、“testAge”:“myage”}output json:{“testname”:“nullgotback”、“testAge”:“nullgotback”}@XmlRootElement公共类inputdt实现可序列化{private static final long serialVersionUID=1L;private String testname;private String testAge;public String getTestname(){返回this.testname;}public void setTestname(String testname){this.testname=testname;}public String getestage(){返回this.testAge;}public void setteststage(String testAge){this.testAge=testAge;}public InputDto(){super();}public InputDto(String testname,String testAge){this.testname=testname;this.testAge=testAge;}尝试过这个方法,但现在在postman上运行时出现错误“客户端发送的请求在语法上不正确。”…您发送的请求是什么?我测试了您的代码,它与您上面给出的请求配合良好。我得到的响应是{“testname”:“mynamegotback”,“testAge”:“myagegotback”}您可以将您的整个服务和文件发送给我吗?如果有,您使用的是哪些头?…我的请求如下:{“testname”:“myname”,“testAge”:“myage”}我正在使用与我提供的代码相同的输入。标题包含Content Type=application/json。请发布修改后的控制器代码,以便我查看一下?