Can'；t使用405允许的后过滤器Java进行修复

现在我遇到了这样的问题，在创建筛选器（（服务器遇到错误，无法完成您的请求。）请在30秒后重试

package com.lumiin.mytalk.filter;

import javax.servlet.*;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
import java.util.logging.Logger;

public class CorsFilter implements Filter {

    private static final Logger log = Logger.getAnonymousLogger();

    @Override
    public void init(FilterConfig filterConfig) throws ServletException {

    }

    @Override
    public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain) throws IOException, ServletException {
        log.info("Adding Access Control Response Headers");
        HttpServletResponse response = (HttpServletResponse) servletResponse;
        response.setHeader("Access-Control-Allow-Origin", "*");
        response.setHeader("Access-Control-Allow-Credentials", "true");
        response.setHeader("Access-Control-Allow-Methods", "POST, GET, HEAD, OPTIONS");
        response.setHeader("Access-Control-Allow-Headers", "Origin, Accept, X-Requested-With, Content-Type, Access-Control-Request-Method, Access-Control-Request-Headers");
        filterChain.doFilter(servletRequest, servletResponse);
    }
    enter code here
    @Override
    public void destroy() {

    }
}

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你能发布你的代码而不是代码的图像吗？当然，看！我贴在那里了！你的

doFilter

方法悬而未决-它应该是

Filter

类的重写方法。否则它不会像你期望的那样工作。如果我为它创建过滤器？@AlexUl我想你应该创建一个过滤器