在DOM(java)中统一节点列表

在DOM(java)中统一节点列表,java,dom,xpath,Java,Dom,Xpath,这是我的密码: private NodeList union(NodeList left, NodeList right){ NodeList result=null; try{ DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); domFactory.setNamespaceAware(true); // never forget this!

这是我的密码:

private NodeList union(NodeList left, NodeList right){

    NodeList result=null;
    try{
        DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
        domFactory.setNamespaceAware(true); // never forget this!

        DocumentBuilder newBuilder = domFactory.newDocumentBuilder();
        Document newDoc = newBuilder.newDocument();

        Element root = newDoc.createElement("root");
        newDoc.appendChild(root);
        if(left!=null){
            for(int i=0;i<left.getLength();i++){
                Node tmp=(Node)left.item(i).cloneNode(true);
                newDoc.adoptNode(tmp);
                newDoc.getDocumentElement().appendChild(tmp);
                //root.appendChild(newDoc.importNode((Node)left.item(i), true));
            }
        }
        if(right!=null){
            for(int i=0;i<right.getLength();i++){
                Node tmp=(Node)right.item(i).cloneNode(true);
                newDoc.adoptNode(tmp);
                newDoc.getDocumentElement().appendChild(tmp);
                //root.appendChild(newDoc.importNode((Node)right.item(i), true));
            }
        }

        result=root.getChildNodes();
    } catch(ParserConfigurationException e){
        System.err.println(e);
    }

    return result;
}
专用节点列表联合(节点列表左侧、节点列表右侧){
节点列表结果=null;
试一试{
DocumentBuilderFactory domFactory=DocumentBuilderFactory.newInstance();
domFactory.setNamespaceAware(true);//永远不要忘记这一点!
DocumentBuilder newBuilder=domFactory.newDocumentBuilder();
Document newDoc=newBuilder.newDocument();
元素根=newDoc.createElement(“根”);
newDoc.appendChild(根);
if(左!=null){

对于(int i=0;i一个节点只能存在于一个文档中。如果希望复制的节点同时存在于两个文档中,那就太倒霉了。只能在目标文档中创建一个新节点,并将子节点和属性从旧节点移动到新节点。查看document::adoptNode(节点),了解最简单的方法是什么