Java 使用“startsWith（）进行字符串搜索”

在过去的几天里，我一直在开发一个电子邮件目录程序，在我的一个方法中，我尝试使用一个搜索功能，根据用户的字符输入搜索电子邮件。我试图使它成为方法循环的地方，用户在电子邮件中一次键入一个字符，直到我为此方法构建的数组中只有一封电子邮件

这是我的密码：

private void searchContact()    
{
    String[] newRecords=new String[emailRecords.size()];        //temp array for searching
    ArrayList<String> searchRecords=new ArrayList<String>();    //to be passed to insertion sort
    newRecords=emailRecords.toArray(newRecords);                

    for(String Records: newRecords) 
    {
        Scanner search=new Scanner(System.in);                  //setup for user input
        String letter;
        String searchVal;

        System.out.println("Please enter the first letter of the email you're trying to find.");
        letter=search.nextLine();

        if (searchRecords.size()!=1)    
        {   
            for (int i=0; i<newRecords.length;i++)          //counter for indexes
            {
                searchVal=newRecords[i];                        //set temp value to set index

                if (searchVal.startsWith(letter))               //starts with boolean
                {
                    searchRecords.add(searchVal);               //add to temp array for later comparison
                }
            }
        }
        else    
        {
            break;                                              //break if one remains in the array.
        }
    }
    System.out.println(searchRecords);                          //TODO erase when finalizing
}

这里是我输入信息并尝试通过输入m、a、r和k来搜索mark后的预期输出：

Please enter the next letter of the email you're trying to find.
m
Please enter the next letter of the email you're trying to find.
a
Please enter the next letter of the email you're trying to find.
r
Please enter the next letter of the email you're trying to find.
k
[mark]

我试图在另一个循环的外部创建另一个同样计数的for循环，并使用它来移动给定字符串的索引，但失败了。我觉得我离得很近，但却忽略了什么。任何建议或策略将不胜感激！非常感谢。

假设emailRecords包含您的所有电子邮件，您的任务如下：

private void searchContact() {
    assert(!(emailRecords == null || emailRecords.isEmpty()));// :P
    //initially copy all
    ArrayList<String> searchRecords = new ArrayList<>(emailRecords);
    //prepare scanner
    Scanner search = new Scanner(System.in);
    //initialize query
    String query = "";
    //loop:
    while (searchRecords.size() > 1) {
        System.out.println("Please enter the first letter of the email you're trying to find.");
        //read from input
        query += search.nextLine();
        //iterate through remaining searchRecords
        for (Iterator<String> it = searchRecords.iterator(); it.hasNext();) {
            final String entry = it.next();
            if (!entry.startsWith(query)) {//...conditionally
                it.remove();//..remove (from searchRecords)
            }
        }
    }
    //print output - first/last of searchRecords
    if (!searchRecords.isEmpty())
        System.out.println(searchRecords.get(0));
    else
        System.out.println("No record found.");
}

---

您可以尝试使用trie数据结构来存储电子邮件地址。trie的一个常见应用是存储预测文本或自动完成字典。。。从

谢谢你的编辑。你期望什么样的产出？我想如果它在你的代码中发现了不止一封邮件，它应该要求更多的信件；更清楚地说，在添加了四条记录之后，是否可以添加另一个包含搜索预期输出的块？就像在当前输出中，您输入了2，但得到了预期的结果。非常感谢。

private void searchContact() {
    assert(!(emailRecords == null || emailRecords.isEmpty()));// :P
    //initially copy all
    ArrayList<String> searchRecords = new ArrayList<>(emailRecords);
    //prepare scanner
    Scanner search = new Scanner(System.in);
    //initialize query
    String query = "";
    //loop:
    while (searchRecords.size() > 1) {
        System.out.println("Please enter the first letter of the email you're trying to find.");
        //read from input
        query += search.nextLine();
        //iterate through remaining searchRecords
        for (Iterator<String> it = searchRecords.iterator(); it.hasNext();) {
            final String entry = it.next();
            if (!entry.startsWith(query)) {//...conditionally
                it.remove();//..remove (from searchRecords)
            }
        }
    }
    //print output - first/last of searchRecords
    if (!searchRecords.isEmpty())
        System.out.println(searchRecords.get(0));
    else
        System.out.println("No record found.");
}