Java 从main调用方法(构造函数)&;文件格式
我有一个构造函数ID3,我需要从main开始执行它。可能吗 我试着这样做:Java 从main调用方法(构造函数)&;文件格式,java,methods,constructor,Java,Methods,Constructor,我有一个构造函数ID3,我需要从main开始执行它。可能吗 我试着这样做: public class ID3 { public static void main(String[] args) throws Exception { System.out.print("\f"); //clears the screen ID3 instance = new ID3("data.txt", 5 , 14 , "", 5); inst
public class ID3
{
public static void main(String[] args) throws Exception
{
System.out.print("\f"); //clears the screen
ID3 instance = new ID3("data.txt", 5 , 14 , "", 5);
instance.ID3("data.txt", 3 , 5 , " ", 2); //error given here since this line had to be removed
}
public ID3(String fName, int numAttributes, int testCases, String delimiter, int limitSplits) throws IOException, FileNotFoundException
{
fileName = fName;
n = numAttributes;
t = testCases;
numSplits = limitSplits;
FileInputStream fstream = new FileInputStream(fileName);
DataInputStream in = new DataInputStream(fstream);
//Parse the first line to see if continuous or discrete attributes.
firstLine = new String[n];
firstLine = in.readLine().split(delimiter);
int i, j, lineCount = 0;
for(i=0; i<n; i++)
unusedAttr.add(new Integer(i));
input = new String[t][n+1];
String line;
int invalidLines = 0;
while((lineCount + invalidLines)<t)
{
try
{
input[lineCount] = (in.readLine()).split(delimiter);
}
catch(NullPointerException e)
{
invalidLines++;continue;
}
if (Array.getLength(input[lineCount]) != n+1 || (Array.get(input[lineCount],n).toString().compareTo("?") == 0)) //number of attributes provided in the line is incorrect.
{
invalidLines++;continue;
}
lineCount++;
}
if(invalidLines == t)
{
System.out.println("All lines invalid - Check the supplied attribute number");
System.exit(0);
}
if (invalidLines > 0)
System.out.println("Not Considering "+invalidLines+" invalid training cases");
if(numSplits > maxSplits || numSplits > (t/2))
{
System.out.println("numSplits should be less than or equal to "+Math.min(t/2,limitSplits));
System.exit(1);
}
t = testCases - invalidLines;
thresholdVal = new String[n][numSplits - 1];
boolean allCont = false;
if(Array.getLength(firstLine) == 1)
{
if(firstLine[0].compareTo("c") == 0)
allCont = true;
else if(firstLine[0].compareTo("d") == 0)
return;
else
{
System.out.println("Invalid first line - it should be c or d");
System.exit(1);
}
}
for(i=0; i<n; i++)
{
if(allCont || firstLine[i].compareTo("c") == 0) //Continuous Attribute
{
for(j=0; j<numSplits-1; j++)
thresholdVal[i][j] = calculateThreshold(i,j);
}
else if(firstLine[i].compareTo("d") != 0)
{
System.out.println("Invalid first line - Training data (it should specify if the attributes are c or d)");
System.exit(1);
}
}
for(i=0; i<t; i++)
{
for(j=0; j<n; j++)
{
if(allCont || firstLine[j].compareTo("c") == 0)
input[i][j] = makeContinuous(input[i][j], j);
}
}
}
您已经在这里调用构造函数-
ID3 instance=new ID3(“data.txt”,5,14,”,5)代码>。不能将其作为常规方法调用。只需删除instance.ID3(“data.txt”,5,14,”,5)代码>行。不能像常规方法那样调用构造函数。当您创建一个类的实例时,即当您
ID3 instance = new ID3("data.txt", 5 , 14 , "", 5);
构造函数不是方法。方法的一个关键特性是它应该有一个返回类型(如果是“void”,则为event)
在这里,您不需要再次显式调用构造函数。在构造函数中实现的功能将在实例化时执行。但是,这是不推荐的,并且容易出现错误。您应该只实例化任何变量。实际功能应该在另一个方法中定义 @user4345738到底什么不起作用?预期的输出是什么?您看到了什么输出?没有显示带有上述参数的输出。应根据算法打印出一棵树implmented@user4345738首先,我不捕获NullPointerException
。您应该避免NullPointerException
,而不是捕获它。如果.readLine()中的in
返回null,这意味着没有更多可用的输入,您应该尝试对null引用调用split
。
ID3 instance = new ID3("data.txt", 5 , 14 , "", 5);