如何在java中将json字符串转换为字节数组

但它首先显示错误

，这不会编译：

String json="{"FROM_JID":"6bc24cac4eaf304ce1731bd5aebe9b0419052701","TO_JID":"dfc8d53f402373a1d3622dde50e180b388b36bc1","TYPE_ID":"1","PLATFORM":"IOS","CONTENT":"{\"FROM_JID\":\"6bc24cac4eaf304ce1731bd5aebe9b0419052701\",\"FROM_HOST\":\"ssdevim.mtouche-mobile.com\",\"FROM_JNAME\":\"test1\",\"TO_JID\":\"dfc8d53f402373a1d3622dde50e180b388b36bc1\",\"TO_HOST\":\"ssdevim.mtouche-mobile.com\",\"MESSAGE_ID\":\"LiYaU-39\",\"MESSAGE_TYPE\":\"enc\",\"MESSAGE\":\"test1 has sent you an encrypted message.\",\"STAMP\":\"2015-11-12 12:04:54.252241\",\"BADGE\":3,\"CONTENT-AVAILABLE\":1,\"SOUND\":\"dafault\"}","DEVICE_ID":"AC53D4F0-DAAA-475E-9668-5E9E7485797C","PUSH_ID":"c9544c8db2117f02f3edc8af9058b3d54c15500302bf6f47c487193876f6dc23","CREATE_DATE":"2015-11-12","CREATE_TIME":"04:04:54"}";
JSONParser parser = new JSONParser();

Object obj = parser.parse(json);

您甚至可以注意到它的语法没有正确突出显示

为了让Java将其识别为字符串的一部分，而不是您的代码，您需要：

String json="{"FROM_JID":"6bc24cac4eaf304ce1731bd5aebe9b0419052701","TO_JID":"dfc8d53f402373a1d3622dde50e180b388b36bc1","TYPE_ID":"1","PLATFORM":"IOS","CONTENT":"{\"FROM_JID\":\"6bc24cac4eaf304ce1731bd5aebe9b0419052701\",\"FROM_HOST\":\"ssdevim.mtouche-mobile.com\",\"FROM_JNAME\":\"test1\",\"TO_JID\":\"dfc8d53f402373a1d3622dde50e180b388b36bc1\",\"TO_HOST\":\"ssdevim.mtouche-mobile.com\",\"MESSAGE_ID\":\"LiYaU-39\",\"MESSAGE_TYPE\":\"enc\",\"MESSAGE\":\"test1 has sent you an encrypted message.\",\"STAMP\":\"2015-11-12 12:04:54.252241\",\"BADGE\":3,\"CONTENT-AVAILABLE\":1,\"SOUND\":\"dafault\"}","DEVICE_ID":"AC53D4F0-DAAA-475E-9668-5E9E7485797C","PUSH_ID":"c9544c8db2117f02f3edc8af9058b3d54c15500302bf6f47c487193876f6dc23","CREATE_DATE":"2015-11-12","CREATE_TIME":"04:04:54"}";

第二，如果您已经有一个

字符串

，并且希望将其转换为

字节[]

，为什么要反序列化它？只需将其转换为

字节

数组：

String json="{\"FROM_JID\":\"6bc24cac4eaf304ce1731bd5aebe9b0419052701\",\"TO_JID\":\"dfc8d53f402373a1d3622dde50e180b388b36bc1\",\"TYPE_ID\":\"1\",\"PLATFORM\":\"IOS\",\"CONTENT\":\"{\\\"FROM_JID\\\":\\\"6bc24cac4eaf304ce1731bd5aebe9b0419052701\\\",\\\"FROM_HOST\\\":\\\"ssdevim.mtouche-mobile.com\\\",\\\"FROM_JNAME\\\":\\\"test1\\\",\\\"TO_JID\\\":\\\"dfc8d53f402373a1d3622dde50e180b388b36bc1\\\",\\\"TO_HOST\\\":\\\"ssdevim.mtouche-mobile.com\\\",\\\"MESSAGE_ID\\\":\\\"LiYaU-39\\\",\\\"MESSAGE_TYPE\\\":\\\"enc\\\",\\\"MESSAGE\\\":\\\"test1 has sent you an encrypted message.\\\",\\\"STAMP\\\":\\\"2015-11-12 12:04:54.252241\\\",\\\"BADGE\\\":3,\\\"CONTENT-AVAILABLE\\\":1,\\\"SOUND\\\":\\\"dafault\\\"}\",\"DEVICE_ID\":\"AC53D4F0-DAAA-475E-9668-5E9E7485797C\",\"PUSH_ID\":\"c9544c8db2117f02f3edc8af9058b3d54c15500302bf6f47c487193876f6dc23\",\"CREATE_DATE\":\"2015-11-12\",\"CREATE_TIME\":\"04:04:54\"}";

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我建议在接触JSON之前，回到java语法…如果我通过显示错误验证字符串JSON，那么它不是一个正确的JSONformat@naveen当然，如果将Java转义字符串粘贴到Jsonlint，则会出现错误。请阅读有关字符转义的文档：，或。这与Java无关，但所有语言的原理都是一样的。如果我使用上述字符串的有效格式，我会在151处的线程“main”意外字符（F）中得到see errors异常。在org.json.simple.parser.Yylex.Yylex（未知源代码）org.json.simple.parser.JSONParser.nextToken（未知源代码）@naveen-Oh，您有一个嵌套的json对象……然后，您还需要转义一个反斜杠。我已经更新了我的答案。

byte[] bytes = json.getBytes();