Java Web服务客户端应用程序

有一个.NETWeb服务，我必须从本地应用程序发送XML数据。我的本地应用程序在Java和Sql上运行

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Web服务正在接受xml类型。你能帮我吗？我该怎么办？有没有这个例子

我给出了java应用程序中的两个示例，您将一个文件发布到服务

Apache HttpClient：

谢谢

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Shiva Kumar SS

Google，你会发现大量的例子。不要期望如此，当你可以做同样的事情时，它会为你提供链接。我已经搜索了谷歌甚至youtube的教程。但我不太明白。我该怎么办。所以，如果有人以前做过同样的申请，他们可能会建议我。从你看到的或读到的东西中，你到底不明白什么？

String url = "https://yoururl.com"; 

HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(url);

// add header
post.setHeader("User-Agent", USER_AGENT);

List<NameValuePair> urlParameters = new ArrayList<NameValuePair>();
urlParameters.add(new BasicNameValuePair("xml", xmlString));

post.setEntity(new UrlEncodedFormEntity(urlParameters));

HttpResponse response = client.execute(post);
System.out.println("\nSending 'POST' request to URL : " + url);
System.out.println("Post parameters : " + post.getEntity());
System.out.println("Response Code : " + 
                            response.getStatusLine().getStatusCode());

BufferedReader rd = new BufferedReader(
                new InputStreamReader(response.getEntity().getContent()));

StringBuffer result = new StringBuffer();
String line = "";
while ((line = rd.readLine()) != null) {
    result.append(line);
}

System.out.println(result.toString());

String url = "http://example.com";
String charset = "UTF-8";
String param1 = URLEncoder.encode("param1", charset);
String param2 = URLEncoder.encode("param2", charset);
String query = String.format("param1=%s&param2=%s", param1, param2);

URLConnection urlConnection = new URL(url).openConnection();
urlConnection.setUseCaches(false);
urlConnection.setDoOutput(true); // Triggers POST.
urlConnection.setRequestProperty("accept-charset", charset);
urlConnection.setRequestProperty("content-type", "application/x-www-form-urlencoded");

OutputStreamWriter writer = null;
try {
    writer = new OutputStreamWriter(urlConnection.getOutputStream(), charset);
    writer.write(query); // Write POST query string (if any needed).
} finally {
    if (writer != null) try { writer.close(); } catch (IOException logOrIgnore) {}
}

InputStream result = urlConnection.getInputStream();
// Now do your thing with the result.