arraylists java中的值组合问题

我正在尝试将冰淇淋和配料串列表中所有可能的串组合起来。但这是：

import java.util.ArrayList;

public class IceCream {
    public long printMenu( ) {
        int scoops[] = {0, 1};
        String iceCream[] = {" ", "chocolate", "vanilla", "strawberry"};
        String toppings[] = {" ", "sprinkles", "whipped cream", "chocolate chips"};
        ArrayList<String> menuList = new ArrayList<String>();
        long menu_num = 0;
        for (int i = 0; i < scoops.length; i++) {
            for (int x = 0; x < iceCream.length; x++) {
                for (int y = 0; y < toppings.length; y++) {
                    menu_num++;
                    if (i == 0) {
                        menuList.add(toppings[y]);
                    }
                    if (i == 1) {
                        if (toppings[y] == toppings[0]) {
                            menuList.add(iceCream[x]);
                        }
                        else {
                            menuList.add(iceCream[x] + toppings[y]);
                        }
                    }
                        System.out.println(menuList);
                    }
                }

            }
            return menu_num;
        }

    public static void main( String [ ] args ) {
        IceCream obj = new IceCream( );
        long count = obj.printMenu( );
        assert count == 32;
    }
}

我不明白为什么它会一次又一次地打印配料，我只想要一个包含所有口味和配料组合的列表。感谢您的帮助

import java.util.ArrayList；
import java.util.ArrayList;

public class IceCream {

public long printMenu( ) 
{
    int scoops[] = {0, 1};
    String iceCream[] = {" ", "chocolate", "vanilla", "strawberry"};
    String toppings[] = {" ", "sprinkles", "whipped cream", "chocolate chips"};

    ArrayList<String> menuList = new ArrayList<String>();
    long menu_num = 0;

    for (int x = 0; x < iceCream.length; x++)
    {
        for (int y = 0; y < toppings.length; y++)
        {
            menu_num++;
            menuList.add(iceCream[x] + " " +  toppings[y]);
        }
    }

        System.out.println(menuList);
        return menu_num;
    }

public static void main( String [ ] args ) {
    IceCream obj = new IceCream( );
    long count = obj.printMenu( );
        System.out.println(count);
    //assert count == 32;
}

公共级冰淇淋{
公共长打印菜单（）
{
int scoops[]={0，1}；
串冰淇淋[]={“，”巧克力“，”香草“，”草莓“}；
串状浇头[]={“，”洒“，”搅打奶油“，”巧克力片“}；
ArrayList menuList=新的ArrayList（）；
长菜单_num=0；
用于（int x=0；x

}

导入java.util.ArrayList；
公共级冰淇淋{
公共长打印菜单（）
{
int scoops[]={0，1}；
串冰淇淋[]={“，”巧克力“，”香草“，”草莓“}；
串状浇头[]={“，”洒“，”搅打奶油“，”巧克力片“}；
ArrayList menuList=新的ArrayList（）；
长菜单_num=0；
用于（int x=0；x

---

}

如何制作，使每种口味都有多个配料？如何制作，使每种口味都有多个配料？

import java.util.ArrayList;

public class IceCream {

public long printMenu( ) 
{
    int scoops[] = {0, 1};
    String iceCream[] = {" ", "chocolate", "vanilla", "strawberry"};
    String toppings[] = {" ", "sprinkles", "whipped cream", "chocolate chips"};

    ArrayList<String> menuList = new ArrayList<String>();
    long menu_num = 0;

    for (int x = 0; x < iceCream.length; x++)
    {
        for (int y = 0; y < toppings.length; y++)
        {
            menu_num++;
            menuList.add(iceCream[x] + " " +  toppings[y]);
        }
    }

        System.out.println(menuList);
        return menu_num;
    }

public static void main( String [ ] args ) {
    IceCream obj = new IceCream( );
    long count = obj.printMenu( );
        System.out.println(count);
    //assert count == 32;
}