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Java Hibernate条件-org.Hibernate.PropertyAccessException:IllegalArgumentException_Java_Hibernate_Orm_Criteria_Hibernate Mapping - Fatal编程技术网

Java Hibernate条件-org.Hibernate.PropertyAccessException:IllegalArgumentException

Java Hibernate条件-org.Hibernate.PropertyAccessException:IllegalArgumentException,java,hibernate,orm,criteria,hibernate-mapping,Java,Hibernate,Orm,Criteria,Hibernate Mapping,我收到以下错误:org.hibernate.PropertyAccessException:IllegalArgumentException调用Part.Part\u id的getter时发生,但我无法将该部件的实例用作对象 String partId = (String)request.getParameter("partid"); Criteria partCriteria = session.createCriteria(PartFeatureVersion.class); partCri

我收到以下错误:
org.hibernate.PropertyAccessException:IllegalArgumentException
调用
Part.Part\u id
的getter时发生,但我无法将该部件的实例用作对象

String partId = (String)request.getParameter("partid");
Criteria partCriteria = session.createCriteria(PartFeatureVersion.class);
partCriteria.add(Restrictions.eq("part",partId ));


@Entity
@Table(name="PART_FEATURE_VERSION")
public class PartFeatureVersion {
private Part part;

@ManyToOne(fetch=FetchType.LAZY)
@JoinColumn(name="part_id")
public Part getPart() {
    return part;
}

在构建croteria时,应该使用part.id而不是part