尝试使用JDBC连接到JavaDerby数据库

尝试使用JDBC连接到JavaDerby数据库,java,jdbc,derby,Java,Jdbc,Derby,我有以下代码: Connection conn = null; Statement stmt = null; // MySQL connection details. String username = ("username"); String password = ("password"); String url = ("jdbc:derby://localhost:1527/OnlineLibrary"); try { /

我有以下代码:

Connection conn = null;
    Statement stmt = null;

    // MySQL connection details.
    String username = ("username");
    String password = ("password");
    String url = ("jdbc:derby://localhost:1527/OnlineLibrary");

    try {

        // Connect to database. 
        Class.forName("org.apache.derby.jdbc.ClientDriver").newInstance();               
        conn = DriverManager.getConnection (url, username, password);            
        stmt = conn.createStatement();

        // Get data.
        String query = ("SELECT PersonNo, Forename, Surname FROM Person;");                       
        ResultSet rs = stmt.executeQuery(query);               
        while (rs.next()) {                
            System.out.println("Person: no: " + rs.getInt("PersonNo") + " name: " + rs.getString("Forename") + " " + rs.getString("Surname"));
        }                 

        // Disconnect from database.
        stmt.close();
        conn.close();
    }
    catch(Exception ex) {
        Java_Utils.printStackTrace("Error connecting to database", ex, true);    
    }        
这给了我:

Error connecting to database
org.apache.derby.client.am.SQLExceptionFactory40.getSQLException(Unknown Source)
org.apache.derby.client.am.SqlException.getSQLException(Unknown Source)
org.apache.derby.client.am.Statement.executeQuery(Unknown Source)
misc.Simple_JDBC_Test.main(Simple_JDBC_Test.java:32)
我觉得一切都很好。我可以使用连接池连接到数据库,但我不理解上面的错误。

@Morgan先生,
使用PreparedStatement代替Statement,表示替换

ResultSet rs=stmt.executeQuery(查询)

ProblemStatement pStmt=dbConnection.prepareStatement(查询)

结果集r=pStmt.executeQuery()


完成此操作后,请显示您的输出

去除半色调在声明末尾签名:

String query = ("SELECT PersonNo, Forename, Surname FROM Person");
然后在OnLineLibrary数据库中直接执行相关查询,以检查其输出以及语法是否正确:

SELECT PersonNo, Forename, Surname FROM Person

第32行是
ResultSet rs=stmt.executeQuery(查询)从不接受异常开始-捕获SQLException并查看它的错误消息是什么。SQL有一个;在没有必要的时候。但我必须使用更好的异常处理。您可以在此处找到一些简单的异常处理代码示例: