Java &引用；旋度-u“；ApacheHttpClient的API密钥授权

我可以使用

restapi

使用

cURL

作为答案。现在我想使用库将其“翻译”为

Java

代码。我只是在添加

API密钥

authorization头时遇到问题：

HttpPost request = new HttpPost(DE_COMPILATION_URL);
byte[] encodedAuth = Base64.encodeBase64(API_KEY.getBytes(StandardCharsets.UTF_8));
String authHeader = "Basic " + new String(encodedAuth);
request.setHeader(HttpHeaders.AUTHORIZATION, authHeader);
request.setHeader("mode", "raw");
request.setHeader("input", "@" + machineCodeFile.toString() + ";filename=" + machineCodeFile.getName());
request.setHeader("architecture", "powerpc");
request.setHeader("endian", "big");
request.setHeader("raw_entry_point", "0x0");
request.setHeader("raw_section_vma", "0x0");
request.setHeader("target_language", "c");

HttpClient client = HttpClientBuilder.create().build();
HttpResponse response = client.execute(request);
String responseBody = EntityUtils.toString(response.getEntity());
System.out.println(responseBody);

这张照片是：

{
    "code": 401,
    "description": "API key authorization failed (missing or invalid API key).",
    "message": "Unauthorized by API Key"
}

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我尝试了不同的授权代码，但都不起作用。有什么问题吗？API键是正确的，可以与

cURL

一起使用。不过，我最后忘记了一个冒号。编码中必须包含以下内容：

HttpPost request = new HttpPost(DE_COMPILATION_URL);
byte[] encodedAuth = Base64.encodeBase64((API_KEY + ":").getBytes(StandardCharsets.UTF_8));
String authHeader = "Basic " + new String(encodedAuth);