Java Groovy数组初始化

我有一个函数，它接受两个位集的输入，然后，我通过在Groovy中求值来调用这个函数。 由于参数是两个位集，我需要内联初始化它们，并通过字符串传递所有内容

public static void main(String[] args) {
    Binding binding = new Binding();
    GroovyShell shell = new GroovyShell(binding);
    path(BitSet.valueOf(new long[] {0b00111111}),BitSet.valueOf(new long[] {0b00000011})); //s3
    //String s1 = "path(BitSet.valueOf([0b00111111L] as long[]),BitSet.valueOf([0b00111111L] as long[]))";
    //String s2 = "path(BitSet.valueOf( long[] o = [0b00111111L] ),BitSet.valueOf( long[] oo = [0b00111111L] ))";
    String s3 = "path(BitSet.valueOf(new long[] {0b00111111}),BitSet.valueOf(new long[] {0b00000011}))";
    Object value = shell.evaluate(s3);


}

public static LinkedList<BitSet> path(BitSet dstBitSet, BitSet srcBitSet) {
    LinkedList<BitSet> l = new LinkedList<>();
    l.add(srcBitSet);
    System.out.println("ok");
    return l;
}

通过谷歌搜索，我发现Groovy接受以下格式的数组序列化：

• [0B0011111]尽可能长[]
• 长[]o=[0B0011111]

正如您从代码中看到的，我尝试在var s1和s2中执行相同的操作，但仍然不起作用。 S1错误为：

Exception in thread "main" groovy.lang.MissingMethodException: No   signature of method: Script1.path() is applicable for argument types:   (java.util.BitSet, java.util.BitSet) values: [{0, 1, 2, 3, 4, 5}, {0, 1,   2, 3, 4, 5}]
Possible solutions: wait(), any(), with(groovy.lang.Closure), each(groovy.lang.Closure), run(), run()

Exception in thread "main" org.codehaus.groovy.control.MultipleCompilationErrorsException: startup failed:
Script1.groovy: 1: Invalid use of declaration inside method call.

S2错误为：

Exception in thread "main" groovy.lang.MissingMethodException: No   signature of method: Script1.path() is applicable for argument types:   (java.util.BitSet, java.util.BitSet) values: [{0, 1, 2, 3, 4, 5}, {0, 1,   2, 3, 4, 5}]
Possible solutions: wait(), any(), with(groovy.lang.Closure), each(groovy.lang.Closure), run(), run()

Exception in thread "main" org.codehaus.groovy.control.MultipleCompilationErrorsException: startup failed:
Script1.groovy: 1: Invalid use of declaration inside method call.

有办法解决这个问题吗？

试试这个：

path(BitSet.valueOf([0b00111111] as long[]), BitSet.valueOf([0b00111111] as long[]))

试试这个：

path(BitSet.valueOf([0b00111111] as long[]), BitSet.valueOf([0b00111111] as long[]))