Java 不能在两个实例中运行同一个类
我尝试使用线程将2个或更多客户端连接到java服务器,但当我尝试多次运行我的类客户端时,它会说 “客户端”不允许并行运行。 你想停止跑步吗 我想要这样的东西Java 不能在两个实例中运行同一个类,java,multithreading,server,parallel-processing,client,Java,Multithreading,Server,Parallel Processing,Client,我尝试使用线程将2个或更多客户端连接到java服务器,但当我尝试多次运行我的类客户端时,它会说 “客户端”不允许并行运行。 你想停止跑步吗 我想要这样的东西 import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.net.ServerSocket; import java.net.Socket; import java.util.ArrayList;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.net.ServerSocket;
import java.net.Socket;
import java.util.ArrayList;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class Server {
private static String[] names = {"Willy", "Felix", "Piotr"};
private static String[] adjs = {"the gentle", "the un-gentle", "the urbane"};
private static final int PORT = 9090 ;
private static ArrayList<ClientHandler> clients = new ArrayList<>();
private static ExecutorService pool = Executors.newFixedThreadPool(5);
public static void main(String[] args) throws IOException {
//utworzenie nowego socketu
ServerSocket listener = new ServerSocket(PORT);
while(true)
{
System.out.println("Serwer czeka na polaczenie...");
//akceptowanie polaczenia
Socket client = listener.accept();
System.out.println("S: Polaczono z klientem");
ClientHandler clientThread = new ClientHandler(client);
clients.add(clientThread);
pool.execute(clientThread);
}
}
public static String getRandomName()
{
String name = names[(int)(Math.random()*names.length)];
String adj = adjs[(int)(Math.random()*adjs.length)];
return name + " " + adj;
}
}
编辑:
我注意到,如果我在cmd中运行这个程序,一切正常,我可以连接2个或更多的客户端,而不会出现任何问题
问题是,由于“并行”错误,我无法在intelliJ中执行此操作
我的代码是这样的
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.net.ServerSocket;
import java.net.Socket;
import java.util.ArrayList;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class Server {
private static String[] names = {"Willy", "Felix", "Piotr"};
private static String[] adjs = {"the gentle", "the un-gentle", "the urbane"};
private static final int PORT = 9090 ;
private static ArrayList<ClientHandler> clients = new ArrayList<>();
private static ExecutorService pool = Executors.newFixedThreadPool(5);
public static void main(String[] args) throws IOException {
//utworzenie nowego socketu
ServerSocket listener = new ServerSocket(PORT);
while(true)
{
System.out.println("Serwer czeka na polaczenie...");
//akceptowanie polaczenia
Socket client = listener.accept();
System.out.println("S: Polaczono z klientem");
ClientHandler clientThread = new ClientHandler(client);
clients.add(clientThread);
pool.execute(clientThread);
}
}
public static String getRandomName()
{
String name = names[(int)(Math.random()*names.length)];
String adj = adjs[(int)(Math.random()*adjs.length)];
return name + " " + adj;
}
}
我一直在试图找出问题所在,但无能为力。有什么想法吗?我正在运行您的代码,但我没有得到错误,也许您需要增加java虚拟机。因为我的默认值是12000MB 要增加java内存,可以执行以下操作
如果没有功能,您需要检查ide,我使用了netbeans非常感谢!我已经安装了netbeans,它很有帮助,我想我在intellij ide中弄乱了一些东西,所以我会尝试卸载它。我做到了,点击了你帖子旁边的v按钮。还可以吗?还有一个问题-您是如何在console中更改名称的?它的运行(服务器)和运行(客户端),我得到了JavaAplication#1、JavaAplication#2等。ide改变了它的
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.net.Socket;
public class ClientHandler implements Runnable{
//zmienne dla socketa i bufferow z dateserver
private Socket client;
private BufferedReader in;
private PrintWriter out;
public ClientHandler(Socket clientSocket) throws IOException {
this.client = clientSocket;
in = new BufferedReader(new InputStreamReader(client.getInputStream()));
out = new PrintWriter(client.getOutputStream(), true);
}
@Override
public void run() {
try{
while (true) {
String request = in.readLine();
if (request.contains("name")) {
out.println(Server.getRandomName());
} else {
out.println("Type 'tell me a name' to get random name");
}
}
} catch (IOException e) {
System.err.println("IO exception in client handler");
System.err.println(e.getStackTrace());
}finally {
out.close();
try {
in.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}