Java 阵列的频率分布
您好,我正在尝试获取文本字体大小和颜色数组的频率,当我有字符串时,我计算频率,我想根据其大小的总体值更改单词和颜色的大小,我尝试除以Java 阵列的频率分布,java,Java,您好,我正在尝试获取文本字体大小和颜色数组的频率,当我有字符串时,我计算频率,我想根据其大小的总体值更改单词和颜色的大小,我尝试除以frequency/average*10但给我空值,但在我的计算器上它给我ie,80/100*10=8,索引为8,字体大小为180 有人能帮我吗 private static int[] fontWeight = { 40, 60, 80, 100, 120, 140, 160,180 }; private static Color[] Colors = { Col
frequency/average*10
但给我空值,但在我的计算器上它给我ie,80/100*10=8,索引为8,字体大小为180
有人能帮我吗
private static int[] fontWeight = { 40, 60, 80, 100, 120, 140, 160,180 };
private static Color[] Colors = { Color.blue, Color.cyan, Color.yellow, Color.green, Color.red,
Color.orange, Color.pink,Color.pink };
//主要
for (String str: wordList) {
int wordFreq = randWord.getFrequency();//assume 80 comes here
int fontSize = getFontSize(wordFreq);
Font font = new Font(Font.SANS_SERIF, Font.ITALIC, fontWeight [fontSize ]);
graphics.setFont(font);
graphics.setColor(Colors[fontSize]);
FontMetrics fm = graphics.getFontMetrics();
graphics.drawString(randWord.getWord() + "", x, y);
}
//方法
private static int getFontSize(int freq) {
int newFont = (int) (freq/100)*10;
if (newFont >= 5) newFont = 6;
// if(newFont<2)
// newFont = 1;
System.out.println("freq " + freq + " font index" + newFont + " font size "
+ fontWeight[newFont]);
return newFont;
}
private static int getFontSize(int freq){
int newFont=(int)(频率/100)*10;
如果(newFont>=5)newFont=6;
//如果(newFont整数除法的行为不同,如果分子小于分母,则结果为0。例如,80/100返回0。您要做的是将分子与10相乘,然后将其除法
int newFont = (int) (freq/100)*10;
应改为
int newFont = (int) (freq*10 / 100);