Java JPA/Hibernate只加入一个选定列

通过

@ManyToOne

    @ManyToOne
    @JoinColumns({
            @JoinColumn(name = "ID", referencedColumnName = "APPLICATION_ID", insertable = false, updatable = false),
            @JoinColumn(name = "VERSION", referencedColumnName = "APPLICATION_VERSION", insertable = false, updatable = false)
    })
    private ApplicationsBodies applicationsBodies;

我加入另一张桌子

但是从联接表中，我只想联接一列

@Entity
@Table
public class ApplicationsBodies implements Serializable {

... 

@Column(name = "APPLICATION_ID")
private Long applicationId;

@Column(name = "APPLICATION_VERSION")
private Long applicationVersion;

//I want to attach only this column
@Lob
@Column(name = "BODY")
private String body;

@Column(name = "ACTIVE_STATE")
private Integer activeState;

如何使用JPA/Hibernate实现这一点

更新：解决方案

我的问题通过

@Formula

注释解决了。因为当我引用一个实体只是为了加载这一个字段时，对我来说它已经成为了最理想的解决方案

---

我删除了字段：

private ApplicationsBodies ApplicationsBodies

。并创建了一个字段：

private String body

with annotation

@Formula

with value-SQL query只连接一列。

如果要使用join with JPA数据，建议使用JPL查询语言。因此，在您的存储库类中，将其用作注释：

@Entity
@Table
public class ApplicationsBodies implements Serializable {

... 

@Column(name = "APPLICATION_ID")
private Long applicationId;

@Column(name = "APPLICATION_VERSION")
private Long applicationVersion;

//I want to attach only this column
@Lob
@Column(name = "BODY")
private String body;

@Column(name = "ACTIVE_STATE")
private Integer activeState;

@Query("select a.name from ApplicationsBodies a join a.applicationId d where d.id = :applicationVersion")

---

谢谢你的回复。我用稍微不同的方式解决了我的问题。更新记录中指出的决定。