Java 在数组列表中显示偶数和奇数时出现问题

对于这个程序，我想在点击“偶数和”按钮时显示偶数及其和，在点击“奇数和”按钮时显示奇数。我已经能够成功地获得偶数和奇数之和，但我无法单独显示偶数和奇数。我正在使用IntelliJ idea和gui

偶和按钮的我的代码：

 BtnSumE.addActionListener(new ActionListener() {
        @Override
        public void actionPerformed(ActionEvent e) {
            int sumE = 0;
            for (int counter = 0; counter < aryNums.size(); counter++) {
                if (aryNums.get(counter) % 2 == 0) {
                    sumE += aryNums.get(counter);
                    TxtArea.setText(String.valueOf(aryNums.get(counter)));
                    TxtArea2.setText("The sum of the even integers is " + valueOf(sumE));
                }

BtnSumO.addActionListener(new ActionListener() {
        @Override
        public void actionPerformed(ActionEvent e) {
            int sumO = 0;
            for (int counter = 0; counter < aryNums.size(); counter++) {
                if (aryNums.get(counter) % 2!= 0) {
                    sumO += aryNums.get(counter);
                    TxtArea.setText(String.valueOf(aryNums.get(counter)));
                    TxtArea2.setText("The sum of the odd integers is " + valueOf(sumO));
                }

BtnSumE.addActionListener（新ActionListener（）{
@凌驾
已执行的公共无效操作（操作事件e）{
总和=0；
对于（int counter=0；counter

奇数和按钮的我的代码：

 BtnSumE.addActionListener(new ActionListener() {
        @Override
        public void actionPerformed(ActionEvent e) {
            int sumE = 0;
            for (int counter = 0; counter < aryNums.size(); counter++) {
                if (aryNums.get(counter) % 2 == 0) {
                    sumE += aryNums.get(counter);
                    TxtArea.setText(String.valueOf(aryNums.get(counter)));
                    TxtArea2.setText("The sum of the even integers is " + valueOf(sumE));
                }

BtnSumO.addActionListener(new ActionListener() {
        @Override
        public void actionPerformed(ActionEvent e) {
            int sumO = 0;
            for (int counter = 0; counter < aryNums.size(); counter++) {
                if (aryNums.get(counter) % 2!= 0) {
                    sumO += aryNums.get(counter);
                    TxtArea.setText(String.valueOf(aryNums.get(counter)));
                    TxtArea2.setText("The sum of the odd integers is " + valueOf(sumO));
                }

BtnSumO.addActionListener（新ActionListener（）{
@凌驾
已执行的公共无效操作（操作事件e）{
国际相扑=0；
对于（int counter=0；counter

当我为偶数和运行程序时，我得到“74”，为奇数和，我得到“263”

我的数组列表（aryNums）有以下数字[0,2,23,74,263]

我已经试过了

TxtArea.setText（String.valueOf（counter））；

对于这两种情况，当我运行它时，偶数和得到“3”，奇数和得到“4”

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任何帮助都将不胜感激：）

在您的情况下，它会在循环的每次迭代中更改文本区域中的总和，我认为您不应该这样做。您需要在声明总和之前完成循环

int sumO = 0;
    for (int counter = 0; counter < aryNums.size(); counter++) {
          if (aryNums.get(counter) % 2!= 0) {
                 sumO += aryNums.get(counter);       
          }
     }
     TxtArea.setText(String.valueOf(aryNums.get(counter)));
     TxtArea2.setText("The sum of the odd integers is " + String.valueOf(sumO)); // you erased the String

intsumo=0；
对于（int counter=0；counter

偶数也一样