Java ApacheWink-在URL中发送JSON字符串
URL为:{\“inputName\”:\“Test\”} 在上面的URL中,我的JSON字符串是{\“inputName\”:\“omsai\”} 我用以下方式调用ApacheWinkREST(POST)调用,但它不起作用。我得到了java.net.URISyntaxExceptionJava ApacheWink-在URL中发送JSON字符串,java,json,rest,apache-wink,Java,Json,Rest,Apache Wink,URL为:{\“inputName\”:\“Test\”} 在上面的URL中,我的JSON字符串是{\“inputName\”:\“omsai\”} 我用以下方式调用ApacheWinkREST(POST)调用,但它不起作用。我得到了java.net.URISyntaxException secHandler.setUserName(userName); secHandler.setPassword(passWord); secHandler.setSSLRequired(false);
secHandler.setUserName(userName);
secHandler.setPassword(passWord);
secHandler.setSSLRequired(false);
ClientConfig clientConfig = new ClientConfig();
clientConfig.handlers(secHandler);
RestClient restClient = new RestClient(clientConfig);
Resource resource = restClient.resource("http://xx.xx.xx.xx:9080/myprocess?action=start¶ms={\"inputName\":\"Test\"}");
String response response = resource.contentType(MediaType.APPLICATION_FORM_URLENCODED_TYPE).accept(MediaType.APPLICATION_JSON).post(String.class,"");
它成功了,这是代码
Here is the code
secHandler.setUserName(userName);
secHandler.setPassword(passWord);
secHandler.setSSLRequired(false);
ClientConfig clientConfig = new ClientConfig();
clientConfig.handlers(secHandler);
RestClient restClient = new RestClient(clientConfig);
Resource resource = restClient.resource("http://xx.xx.xx.xx:9080/myprocess?action=start
String jsonString ="params={\"inputName\":\"Test\"}")";
String response response = resource.contentType(MediaType.APPLICATION_FORM_URLENCODED_TYPE).accept(MediaType.APPLICATION_JSON).post(String.class,jsonString);