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在Java中打印一段单词中的每个单词,同时使用Scanner类跳过一些单词_Java_Java.util.scanner_Nosuchelementexception - Fatal编程技术网

在Java中打印一段单词中的每个单词,同时使用Scanner类跳过一些单词

在Java中打印一段单词中的每个单词,同时使用Scanner类跳过一些单词,java,java.util.scanner,nosuchelementexception,Java,Java.util.scanner,Nosuchelementexception,我正在写一个程序来接收一个文件并输出一个文件。 输入文件包含以下内容: 1 cat dog rabbit 3 cat dog rabbit rabbit rabbit 2 yellow red blue white black 0 three two one 输出文件为: dog rabbit rabbit rabbit blue white black three two one (程序在每行开头输入整数,然后跳过每行中的字数,然后保存其余的字并将其

我正在写一个程序来接收一个文件并输出一个文件。 输入文件包含以下内容:

    1 cat dog rabbit
    3 cat dog rabbit rabbit rabbit
    2 yellow red blue white black
    0 three two one
输出文件为:

    dog rabbit rabbit rabbit blue white black three two one
(程序在每行开头输入整数,然后跳过每行中的字数,然后保存其余的字并将其输出到文件中)

起初,我有

import java.util.Scanner;
import java.io.FileNotFoundException;
import java.io.File;
import java.io.PrintWriter;

public class Scanner2{
    public static void main(String args[]) {
        String c = "";
        try{
            File file = new File(args[0]);
            Scanner scanner = new Scanner(file); 
            PrintWriter writer = new PrintWriter(args[1]);
        // as long as the scanner reads that the file has a next line
               while (scanner.hasNextLine()) {    
        // read the next line of string as string s
                   String s = scanner.nextLine(); 
        // split each word from the string s as an array called "words"
                   String[] words = s.split(" ");
        // for loop executed length of "words" times
                   for(int x = 0; x < words.length; x++) {
        // declare int, "count"
                       int count;
        // parse the first element (the number) from "words" to be an integer, "count"
                       count = Integer.parseInt(words[0]);
        // if the loop is executed more than "count" number of times
                       if (x > count){
        // add respective element to string, "c"
                           c += words[x];
                           c += " ";
                    }
                }
            }
        // close the scanner
            scanner.close();
        // output string "c" to the output file
            writer.println(c);
        // close the writer
            writer.close();
    }
        catch (FileNotFoundException e) {
            e.printStackTrace();
   }      
   }
}
在for循环中


感谢您的帮助。谢谢,但我对Java真的很陌生,

例如,您可以使用StringTokenizer而不是第二个扫描程序:

while(scanner.hasNextLine())
{
    StringTokenizer tokenizer = new StringTokenizer(scanner.nextLine());
    int count = Integer.parseInt(tokenizer.nextToken());

    while(tokenizer.hasMoreTokens())
    {
        String b = tokenizer.nextToken() + " ";

        if(count <= 0)
        {
            c += b;
        }
        count--;
    }
}
scanner.close();
while(scanner.hasNextLine())
{
StringTokenizer tokenizer=新的StringTokenizer(scanner.nextLine());
int count=Integer.parseInt(tokenizer.nextToken());
while(tokenizer.hasMoreTokens())
{
字符串b=tokenizer.nextToken()+“”;

如果(count嵌套的while和for循环中有一个bug,导致for循环中的s2.next()走到行的末尾。请尝试以下操作

            // parse the string "counts" as int, "count"
            int count = Integer.parseInt(counts);
            // for loop executed "count" number of times to skip the words
            for (int x = 0; x < count && s2.hasNext(); x++){
                String b = s2.next();
            }
            // as long as s2 has the next element add the next words to string
            while (s2.hasNext()) {
                c += s2.next();
                c += " ";
            }
这样,即使引发异常,
扫描仪
写入程序
也会自动关闭

while(scanner.hasNextLine())
{
    StringTokenizer tokenizer = new StringTokenizer(scanner.nextLine());
    int count = Integer.parseInt(tokenizer.nextToken());

    while(tokenizer.hasMoreTokens())
    {
        String b = tokenizer.nextToken() + " ";

        if(count <= 0)
        {
            c += b;
        }
        count--;
    }
}
scanner.close();
            // parse the string "counts" as int, "count"
            int count = Integer.parseInt(counts);
            // for loop executed "count" number of times to skip the words
            for (int x = 0; x < count && s2.hasNext(); x++){
                String b = s2.next();
            }
            // as long as s2 has the next element add the next words to string
            while (s2.hasNext()) {
                c += s2.next();
                c += " ";
            }
    try (Scanner scanner = new Scanner(file);
         PrintWriter writer = new PrintWriter(args[1]);) {
        scanner.next();   
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }