玩2.2.1 Java Ebean-Finder.select（字符串列）不'；t工作：所有列都已选中

我在使用ebean和Play时遇到了对象的select函数的问题！框架（2.2.1）

我有我的桌子退火运动：

CREATE TABLE AnneePromotion (
  anneePromotion_ID INTEGER NOT NULL PRIMARY KEY DEFAULT nextval('AnneePromotionSequence'),
  anneePromotion_libelle INTEGER NOT NULL 
);

@Entity
@Table(name = "AnneePromotion")
@SequenceGenerator(name = "AnneePromotionSequenceGenerator", sequenceName =         "AnneePromotionSequence")
public class AnneePromotion extends Model {

    /** serial ID */
    private static final long serialVersionUID = -2072489268439045171L;

    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "AnneePromotionSequenceGenerator")
    @Column(name = "anneePromotion_ID")
    private Integer id;

    @Column(name = "anneePromotion_libelle")
    private String libelle;

    public Integer getId() {
        return id;
    }

    public String getLibelle() {
        return libelle;
    }

    public void setLibelle(String libelle) {
        this.libelle = libelle;
    }

    public static Finder<Integer, AnneePromotion> find = new Finder<Integer, AnneePromotion>(
        Integer.class, AnneePromotion.class);

}

我的实体AnneePromotion：

CREATE TABLE AnneePromotion (
  anneePromotion_ID INTEGER NOT NULL PRIMARY KEY DEFAULT nextval('AnneePromotionSequence'),
  anneePromotion_libelle INTEGER NOT NULL 
);

@Entity
@Table(name = "AnneePromotion")
@SequenceGenerator(name = "AnneePromotionSequenceGenerator", sequenceName =         "AnneePromotionSequence")
public class AnneePromotion extends Model {

    /** serial ID */
    private static final long serialVersionUID = -2072489268439045171L;

    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "AnneePromotionSequenceGenerator")
    @Column(name = "anneePromotion_ID")
    private Integer id;

    @Column(name = "anneePromotion_libelle")
    private String libelle;

    public Integer getId() {
        return id;
    }

    public String getLibelle() {
        return libelle;
    }

    public void setLibelle(String libelle) {
        this.libelle = libelle;
    }

    public static Finder<Integer, AnneePromotion> find = new Finder<Integer, AnneePromotion>(
        Integer.class, AnneePromotion.class);

}

我不知道选择功能是否起作用，我是否犯了愚蠢的错误：/

希望你能帮助我

---

您好，Anthony。

这是Ebean的常见行为，原因很简单：您请求的是具体类型的对象列表，因此它不能只返回字符串列表（没有

id

），因为它需要以某种方式标识行

最简单的解决方案是将其改写为新列表

List<String> libelles = new ArrayList<>();
for (AnneePromotion anneepromotion : listeDesAnneesdePromotion){
    libelles.add(anneepromotion.getLibelle());
}

List libelles=new ArrayList（）；
对于（退火推进退火推进：ListedAnneesDePromotion）{
add（anneepromotion.getLibelle（））；
}

您还可以选择使用Ebean，然后遍历

---

要获得相同的

libelles

list.

BTW，为什么不在模型中使用公共字段？您不需要创建getter和setter。我不喜欢公共字段^^谢谢，我会这样做，然后尝试SqlQuery