Java 尝试解析JSON对象时强制关闭Android

我已经使用jersey创建了RESTWeb服务，它返回JSON响应。web服务返回的JSON响应如下-

{
  "Disease": "Bacterial_blight",
  "Control": "Foliar sprays of streptocycline sulphate @ 0.5 gm/land copper-oxychlode @ 3 g / l of water as and when symptoms seen."
}

我制作了Android应用程序活动，用于演示，其中包含一个单选按钮、一个编辑文本框和一个按钮，用于向REST web服务提交参数。但问题是，当我试图点击提交按钮时，我已经迫在眉睫了

这是实际的android活动类代码-

package com.doitgeek.agroadvisorysystem;

import android.app.ProgressDialog;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.RadioButton;
import android.widget.TextView;
import android.widget.Toast;

import com.loopj.android.http.AsyncHttpClient;
import com.loopj.android.http.AsyncHttpResponseHandler;
import com.loopj.android.http.RequestParams;

import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import org.json.JSONTokener;

public class DiseaseResultActivity extends AppCompatActivity {
    public TextView diseaseTV;
    public TextView controlMechanismTV;
    public EditText etSymptom;
    public RadioButton rbL;
    public Button btnSubmit;
    ProgressDialog dialog;


    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_disease_result);

        diseaseTV = (TextView)findViewById(R.id.diseaseTV);
        controlMechanismTV = (TextView)findViewById(R.id.controlMechanismTV);
        etSymptom = (EditText)findViewById(R.id.etSymptom);
        rbL = (RadioButton)findViewById(R.id.rbL1);
        btnSubmit = (Button)findViewById(R.id.btnSubmit);

    }

    public void onClickSubmit(View view) {
        RequestParams params = new RequestParams();
        String affectedPart = rbL.getText().toString();
        String symptom = etSymptom.getText().toString();
        params.put("affectedPart", affectedPart);
        params.put("symptom", symptom);
        invokeWS(params);
    }

    /* Invocation of RESTful WS */
    public void invokeWS(RequestParams params) {
        dialog.show();
        AsyncHttpClient client = new AsyncHttpClient();
        client.get("http://192.168.0.100:8080/AgroAdvisorySystem/webapi/disease_prediction/result", params, new AsyncHttpResponseHandler(){
            @Override
            public void onSuccess(String response) {
                dialog.hide();
                try {
                    JSONObject obj = (JSONObject)new JSONTokener(response.toString()).nextValue();
                    JSONObject obj2 = obj.getJSONObject("Disease");
                    String disease = obj2.toString();
                    /*JSONObject obj = new JSONObject(response);
                    String disease = obj.getJSONObject("Disease").toString();*/
                    diseaseTV.setText(disease);

                } catch (JSONException e) {
                    Toast.makeText(getApplicationContext(), "Error Occurred [Server's JSON response might be invalid]!", Toast.LENGTH_LONG).show();
                    e.printStackTrace();
                }
            }

            @Override
            public void onFailure(int statusCode, Throwable error, String content) {
                dialog.hide();
                if(statusCode == 404) {
                    Toast.makeText(getApplicationContext(), "Requested resource not found", Toast.LENGTH_LONG).show();
                } else if(statusCode == 500) {
                    Toast.makeText(getApplicationContext(), "Something went wrong at server end", Toast.LENGTH_LONG).show();
                } else {
                    Toast.makeText(getApplicationContext(), "Unexpected Error occurred! [Most common Error: Device might not be connected to Internet or remote server is not up and running]", Toast.LENGTH_LONG).show();
                }
            }
        });
    }
}

---

直到现在，我还没有找到有效的解决方案，这就是为什么我把这个问题作为问题发布。

那么，异常记录是什么

问题似乎在于：

JSONObject obj2=obj.getJSONObject（“疾病”）

其中项目
Disease
不再是
JSONObject

试试看“疾病”

obj.getSyting（“疾病”）