Java 我在启动服务器时遇到以下问题。找不到URL为的HTTP请求的映射
如何解决这个问题。我有index.jsp,但它没有打开该jsp我能做什么 错误是:在名为“rest”的DispatcherServlet中找不到URI为[/RoomController/]的HTTP请求的映射 web.xml:Java 我在启动服务器时遇到以下问题。找不到URL为的HTTP请求的映射,java,jsp,spring-mvc,Java,Jsp,Spring Mvc,如何解决这个问题。我有index.jsp,但它没有打开该jsp我能做什么 错误是:在名为“rest”的DispatcherServlet中找不到URI为[/RoomController/]的HTTP请求的映射 web.xml: <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.c
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaeehttp://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>SpringServiceJsonSample</display-name>
<servlet>
<servlet-name>rest</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>rest</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>Index.jsp</welcome-file>
</welcome-file-list>
</web-app>
SpringServiceJsonSample
休息
org.springframework.web.servlet.DispatcherServlet
1.
休息
/*
Index.jsp
rest-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd">
<context:property-placeholder location="classpath:resources/database.properties" />
<context:component-scan base-package="com.Room" />
<tx:annotation-driven transaction-manager="hibernateTransactionManager"/>
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${database.driver}" />
<property name="url" value="${database.url}" />
<property name="username" value="${database.user}" />
<property name="password" value="${database.password}" />
</bean>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="annotatedClasses">
<list>
<value>com.Room.Model.RoomMembers</value>
<value>com.Room.Model.MemberInOut</value>
<value>com.Room.Model.RoomDetails</value>
</list>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">${hibernate.dialect}</prop>
<prop key="hibernate.show_sql">${hibernate.show_sql}</prop>
<prop key="hibernate.hbm2ddl.auto">${hibernate.hbm2ddl.auto}</prop>
</props>
</property>
</bean>
<bean id="hibernateTransactionManager"
class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
</bean>
<mvc:annotation-driven />
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/"/>
<property name="suffix" value=".jsp"/>
</bean>
com.Room.Model.RoomMembers
com.Room.Model.MemberInOut
com.Room.Model.RoomDetails
${hibernate.dial}
${hibernate.show_sql}
${hibernate.hbm2ddl.auto}
控制器类为:
@RestController
@RequestMapping("/Room/")
public class RoomController {
@Autowired
RoomDao roomDao;
@RequestMapping(method = RequestMethod.GET,headers="Accept=application/json")
public String getAllUsers() {
String users="hello welcome ";
return users;
}
@RequestMapping(value="/ViewMember",method = RequestMethod.GET)
public List<RoomMembers> getRoomMembers() {
List<RoomMembers> roomMemberList= new ArrayList<RoomMembers>();
roomMemberList=roomDao.listMember();
return roomMemberList;
}
@RestController
@请求映射(“/Room/”)
公共教室管理员{
@自动连线
RoomDao RoomDao;
@RequestMapping(method=RequestMethod.GET,headers=“Accept=application/json”)
公共字符串getAllUsers(){
String users=“hello welcome”;
返回用户;
}
@RequestMapping(value=“/ViewMember”,method=RequestMethod.GET)
公共列表getRoomMembers(){
List roomMemberList=新建ArrayList();
roomMemberList=roomDao.listMember();
返回roomMemberList;
}
您的映射配置不正确。您可以使用@RequestMapping
将控制器与URI映射,方法是在其中指定值
属性,如下所示:
@RequestMapping(value="/")
public String displayGui(ModelMap model) {
// Add value to model
model.addAttribute(...);
model.addAttribute(...);
//return to view index.jsp
return "index";
}
@请求映射(值=“”)
因此,当您定义上述控制器时,您可以通过
/Room/
而不是/RoomController访问它,控制器中应该有一个默认映射为“/RoomController”的方法,该方法返回index.jsp作为视图部分,如下所示:
@RequestMapping(value="/")
public String displayGui(ModelMap model) {
// Add value to model
model.addAttribute(...);
model.addAttribute(...);
//return to view index.jsp
return "index";
}
因此,当您点击时,将调用上面的displayGui方法,并返回index.jsp/i was remove/Room/意味着它下载了一个json文件,我想打开index.jsp。那么,如果您想访问index.jsp,那么我想做什么更改呢?只需使用
@Controller
注释,其中一个方法定义为提供视图名称作为返回值。