Java 如何编辑json列表？

我有一个列表，我把这个列表放在json对象中，我想用jquery迭代这个列表，我需要附加到表中。有人能帮我解决这个问题吗

这是我的动作课

    String startdate = request.getParameter("startdate");
    String endate = request.getParameter("endate");
    String leavepolicyid = request.getParameter("leavepolicyid");
    Session session = HibernateUtil.getSessionFactory().openSession();
    LeavePolicyEntity lpe = (LeavePolicyEntity) session.get(LeavePolicyEntity.class, Integer.parseInt(leavepolicyid));
    SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
    Calendar fromcal = Calendar.getInstance();
    fromcal.setTime(sdf.parse(startdate));
    Calendar endCal = Calendar.getInstance();
    endCal.setTime(sdf.parse(endate));
    int actualDays = 0;
    boolean excludeWeekends = lpe.isExcludeweekends();
    int totalDays = 0;
    List daysList = new ArrayList();
    StringBuffer sb = new StringBuffer();
    SimpleDateFormat dateFormat = new SimpleDateFormat("EEE", Locale.US);
    SimpleDateFormat sdf1 = new SimpleDateFormat("dd-MMM-yyyy");

    while (!fromcal.after(endCal)) {
        sb.setLength(0);
        System.out.println("fromcal.get(Calendar.DAY_OF_WEEK)" + fromcal.get(Calendar.DAY_OF_WEEK));
        if (excludeWeekends) {
            if ((7 != fromcal.get(Calendar.DAY_OF_WEEK)) && (1 != fromcal.get(Calendar.DAY_OF_WEEK))) {
                actualDays++;
//                  String asWeek = dateFormat.format(fromcal.getTime());
                sb.append(dateFormat.format(fromcal.getTime()) + "-" + sdf1.format(fromcal.getTime()) + ",true");
            } else {
                sb.append(dateFormat.format(fromcal.getTime()) + "-" + sdf1.format(fromcal.getTime()) + ",false");
            }
        } else {
            sb.append(dateFormat.format(fromcal.getTime()) + "-" + sdf1.format(fromcal.getTime()) + ",true");
            actualDays++;
        }
        daysList.add(sb.toString());
        fromcal.add(Calendar.DATE, 1);
        totalDays++;
    }
//        System.out.println("daysListdaysListdaysList" + daysList);
//        JSONObject json = new JSONObject();
//        json.accumulate("weekdays", daysList);

    response.setContentType("application/json");
    String json = new Gson().toJson(daysList);
    System.out.println("Json" + json);
    response.getWriter().print(json); 

Jquery ajax

 $("[id^='leavetype']").change(function() {
        var startdate = $('#leavetypefromdate').val();
        var enddate = $('#leavetypetodate').val();
//        alert(startdate)
//        alert(enddate)
        if (startdate != "" && enddate != "") {
            if (new Date(startdate) <= new Date(enddate)) {
                $.get("leaverequestvalidation.do?method=validateleavetype", {startdate: startdate, endate: enddate, leavepolicyid: $('#leaveTypeid').val()}, function(responce) {
                    alert(responce);
                    $.each(JSON.parse(responce), function(idx, obj) {
                        alert(1);
                    });

                });
            } else {

                alert("FromDate Cannot Be Greater Than ToDate")
            }
        }
    });

$（“[id^='leavetype']”）。更改（函数（）{
var startdate=$（'#leavetypefromdate'）.val（）；
var enddate=$（'#leveTypeToDate'）.val（）；
//警报（起始日期）
//警报（结束日期）
如果（开始日期！=“”&结束日期！=“”）{
如果（new Date（startdate），如果你只是在这里发布你的JSON对象会有帮助吗？我已经发布了没有ajax调用的所有代码。这样答案就可以从jquery的ajax调用开始，更容易阅读。我已经更新了我的代码。