使用javascript删除与对象的另一个键和值对相对应的对象数组中的重复项
有一个对象数组,对象有两个键和值对使用javascript删除与对象的另一个键和值对相对应的对象数组中的重复项,javascript,arrays,javascript-objects,keyvaluepair,Javascript,Arrays,Javascript Objects,Keyvaluepair,有一个对象数组,对象有两个键和值对 [{fruit:"apple",locale:"US"}, {fruit:"orange",locale:"US"}, {fruit:"banana",locale:"US"}, {fruit:"apple",locale:"US"}, {fruit:"orange",locale:"IT"}, {fruit:"apple",locale:"IT"}, {fruit:"banana",locale:"IT"}, {fruit:"orange",locale:"
[{fruit:"apple",locale:"US"},
{fruit:"orange",locale:"US"},
{fruit:"banana",locale:"US"},
{fruit:"apple",locale:"US"},
{fruit:"orange",locale:"IT"},
{fruit:"apple",locale:"IT"},
{fruit:"banana",locale:"IT"},
{fruit:"orange",locale:"IT"}
{fruit:"apple",locale:"IT"}]
如何实现
水果不应在同一区域内重复,
水果在不同的地区可以是相同的。您可以通过匹配当前迭代的索引值来筛选出对象。大概是这样的:
var data=[{fruit:“apple”,locale:“US”},{fruit:“US”},{fruit:“banana”,locale:“US”},{fruit:“apple”,locale:“US”},{fruit:“apple”,locale:“IT”},{fruit:“banana”,locale:“IT”},{fruit:“apple”,locale:“IT”};
var result=data.filter((e,i,self)=>self.findIndex(k=>k.fruit==e.fruit&&k.locale==e.locale)==i);
控制台日志(结果)代码>您可以通过匹配当前迭代的索引值筛选出对象。大概是这样的:
var data=[{fruit:“apple”,locale:“US”},{fruit:“US”},{fruit:“banana”,locale:“US”},{fruit:“apple”,locale:“US”},{fruit:“apple”,locale:“IT”},{fruit:“banana”,locale:“IT”},{fruit:“apple”,locale:“IT”};
var result=data.filter((e,i,self)=>self.findIndex(k=>k.fruit==e.fruit&&k.locale==e.locale)==i);
控制台日志(结果)代码>试试这个
obj = [{fruit:"apple",locale:"US"},
{fruit:"orange",locale:"US"},
{fruit:"banana",locale:"US"},
{fruit:"apple",locale:"US"},
{fruit:"orange",locale:"IT"},
{fruit:"apple",locale:"IT"},
{fruit:"banana",locale:"IT"},
{fruit:"orange",locale:"IT"}
{fruit:"apple",locale:"IT"}]
const uniqueArray = this.obj.filter((item, index) => {
const temp = JSON.stringify(item);
return index === this.obj.findIndex(obj => {
return JSON.stringify(obj) === temp;
});
});
console.log(uniqueArray);
试试这个
obj = [{fruit:"apple",locale:"US"},
{fruit:"orange",locale:"US"},
{fruit:"banana",locale:"US"},
{fruit:"apple",locale:"US"},
{fruit:"orange",locale:"IT"},
{fruit:"apple",locale:"IT"},
{fruit:"banana",locale:"IT"},
{fruit:"orange",locale:"IT"}
{fruit:"apple",locale:"IT"}]
const uniqueArray = this.obj.filter((item, index) => {
const temp = JSON.stringify(item);
return index === this.obj.findIndex(obj => {
return JSON.stringify(obj) === temp;
});
});
console.log(uniqueArray);
它可能涉及迭代数组并存储一个值,如fruit locale,然后如果得到一个重复的值,则从数组中拼接它。您尝试过什么?您期望的输出是什么?它可能涉及到在数组上迭代并存储一个值,如fruit locale,然后如果您得到一个重复的值,请从数组中拼接它。你尝试过什么?你期望的结果是什么?