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Javascript 节点sequelize回调函数,是否有方法通过函数调用删除声明的函数_Javascript_Node.js_Promise_Jshint_Sequelize.js - Fatal编程技术网

Javascript 节点sequelize回调函数,是否有方法通过函数调用删除声明的函数

Javascript 节点sequelize回调函数,是否有方法通过函数调用删除声明的函数,javascript,node.js,promise,jshint,sequelize.js,Javascript,Node.js,Promise,Jshint,Sequelize.js,我对节点sequelize库有问题。使用成功承诺时,如下所示: for (index = 0; index < models.length; index++) { model = models[index]; model.drop().success(function() { dropTableCompleteCheck(); }); } 我试图调用successpromise回调函数,同时删除JSHint问题。有没有另外一种方法可以同时做

我对节点sequelize库有问题。使用成功承诺时,如下所示:

for (index = 0; index < models.length; index++) {
     model = models[index];
     model.drop().success(function() {
         dropTableCompleteCheck();
     });
}
我试图调用successpromise回调函数,同时删除JSHint问题。有没有另外一种方法可以同时做到这两个方面,我很乐意接受任何建议

谢谢您的时间。

省略括号:

for (index = 0; index < models.length; index++) {
    model = models[index];
    //don't _invoke_ dropTableCompleteCheck, just _reference_ it
    model.drop().success(dropTableCompleteCheck);
}
for(索引=0;索引
error: Uncaught application error:
    TypeError: listener must be a function
for (index = 0; index < models.length; index++) {
    model = models[index];
    //don't _invoke_ dropTableCompleteCheck, just _reference_ it
    model.drop().success(dropTableCompleteCheck);
}