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Javascript 我需要一个逻辑代码来创建下面的json结构dynamicaly_Javascript_Jquery_Angularjs_Json - Fatal编程技术网

Javascript 我需要一个逻辑代码来创建下面的json结构dynamicaly

Javascript 我需要一个逻辑代码来创建下面的json结构dynamicaly,javascript,jquery,angularjs,json,Javascript,Jquery,Angularjs,Json,我需要一个逻辑代码来创建json结构DynamicCaly 我用下面的代码切碎了JSON,它工作得很好,但我需要像上面JSON结构一样的列表 { "2016-01-02": { command: 5, url: "" }, "2015-05-26": { command: 1, url: "" }, "2015-05-03": { command: 2, url: "" }, } 输出 $.each(databaseData, function (ind, val) { var dateFo

我需要一个逻辑代码来创建json结构DynamicCaly

我用下面的代码切碎了JSON,它工作得很好,但我需要像上面JSON结构一样的列表

{
"2016-01-02": { command: 5, url: "" },
"2015-05-26": { command: 1, url: "" },
"2015-05-03": { command: 2, url: "" },
}
输出

$.each(databaseData, function (ind, val) { 
var dateFormated = val.date; //This data comming from database
var jsonFormatedDate = dateFormated;
jsonFormatedData[jsonFormatedDate] = { "command": val.command, "url":   val.url      }
console.log(jsonFormatedData)
});

您可能希望将对象保持在循环之外


您可能希望将对象保持在循环之外


我认为这很好,尝试向
jsonformatteddata
添加更多项目。我认为这很好,尝试向
jsonformatteddata
添加更多项目
{
"2016-01-02": { command: 5, url: "" }
}
var jsonFormatedDate = {};

$.each(databaseData, function (ind, val) { 
    jsonFormatedData[val.date] = { command: val.command, url: val.url};
});

console.log(jsonFormatedDate)