如何在数组中找到多个元素-Javascript，ES6

代码：

如何从数组名称中获取包含“s”的名称， 目前，我得到的结果只有一个元素，但我需要所有出现的元素。

您必须在此上下文中使用

let names= ["Style","List","Raw"];
let results= names.find(x=> x.includes("s");
console.log(results); // 

如果希望它不区分大小写，请使用以下代码

let names= ["Style","List","Raw"];
let results= names.filter(x => x.includes("s"));
console.log(results); //["List"]

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要使其区分大小写，我们必须将字符串的字符全部改为小写。

使用filter而不是find

let names= ["Style","List","Raw"];
let results= names.filter(x => x.toLowerCase().includes("s"));
console.log(results); //["Style", "List"]

---

但也可以使用forEach（）方法：

或者，如果您愿意：

var names = ["Style","List","Raw"];
var results = [];
names.forEach(x => {if (x.includes("s") || x.includes("S")) results.push(x)});
console.log(results); // [ 'Style', 'List' ]

---

如果使用过滤器，则在forEach中执行的操作将由过滤器完成。筛选器返回数组，而forEach不会返回任何内容。所以它可读性更好：）太好了

var names = ["Style","List","Raw"];
var results = [];
names.forEach(x => {if (x.includes("s") || x.includes("S")) results.push(x)});
console.log(results); // [ 'Style', 'List' ]

names.forEach(x => {if (x.toLowerCase().includes("s")) results.push(x)});