Javascript 访问Dojo请求上的http正文错误
我的Web服务在http正文中提供了有关occoured错误的详细信息。 如何在dojo请求中访问此详细信息 例如,http错误如下所示:Javascript 访问Dojo请求上的http正文错误,javascript,ajax,dojo,request,Javascript,Ajax,Dojo,Request,我的Web服务在http正文中提供了有关occoured错误的详细信息。 如何在dojo请求中访问此详细信息 例如,http错误如下所示: HTTP/1.1 500 Internal Server Error Transfer-encoding: chunked Content-type: application/json Date: Tue, 18 Sep 2012 18:47:31 GMT 15 This is my exception! 0 require(["dojo/dom", "
HTTP/1.1 500 Internal Server Error
Transfer-encoding: chunked
Content-type: application/json
Date: Tue, 18 Sep 2012 18:47:31 GMT
15
This is my exception!
0
require(["dojo/dom", "dojo/on", "dojo/request",
"dojo/json", "dojo/domReady!"],
function(dom, on, request, JSON){
// Results will be displayed in resultDiv
var resultDiv = dom.byId("errorResult");
// Attach the onclick event handler to the makeRequest button
on(dom.byId('errorButton'),"click", function(evt){
request.get("./rest/test/error", {
// Parse data from JSON to a JavaScript object
handleAs: "json"
}).then(function(data){
resultDiv.innerHTML = "Username: " + data.name + "</br>Role:" + data.role;
},
function(error){
// Display the error returned
resultDiv.innerHTML = error;
});
});
}
);
我的Dojo请求如下所示:
HTTP/1.1 500 Internal Server Error
Transfer-encoding: chunked
Content-type: application/json
Date: Tue, 18 Sep 2012 18:47:31 GMT
15
This is my exception!
0
require(["dojo/dom", "dojo/on", "dojo/request",
"dojo/json", "dojo/domReady!"],
function(dom, on, request, JSON){
// Results will be displayed in resultDiv
var resultDiv = dom.byId("errorResult");
// Attach the onclick event handler to the makeRequest button
on(dom.byId('errorButton'),"click", function(evt){
request.get("./rest/test/error", {
// Parse data from JSON to a JavaScript object
handleAs: "json"
}).then(function(data){
resultDiv.innerHTML = "Username: " + data.name + "</br>Role:" + data.role;
},
function(error){
// Display the error returned
resultDiv.innerHTML = error;
});
});
}
);
我想要的是正文中的文本:
This is my exception!
当我将dojo用于Ajax请求时,error方法总是有多个参数。我认为第一个参数是发送的请求,第二个参数是响应或异常
尝试向方法中添加第二个参数,看看是否包含所需的参数。看看我的答案 使用
deferred.response。然后
而不是deferred。然后
:
var deferred = request.get("./rest/test/error", { handleAs: "json" });
deferred.response.then(
// success
function(response) {
console.log("data:", response.data); // parsed json
console.log("http body:", response.text); // raw text
},
// error
function(error) {
var response = error.response;
console.log("http body:", response.text);
}
);
在jsFiddle上查看它的实际操作:您的意思是这样的:函数(错误,测试){alert(测试);}这将发出警报:undefinedok这意味着没有传递第二个参数,所以我上面的注释是错误的。我刚刚注意到您的内容类型设置为application/json,但您的正文是纯文本。不确定这是否是一个问题,但可以在某个地方开始调试